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Lunna [17]
4 years ago
11

A rectangle has a length of 9.00 inches and a width of 4.25 inches. What us the area in square inches? Round to the correct sign

ificant digits
Mathematics
1 answer:
gregori [183]4 years ago
5 0
9.00 x 4.25 = 38.25

If we round it, it will be 38 inches

So the area is 38in^2

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The function f(x) = 3x² + 12x +11 can be written in
Viktor [21]

Answer:

3)  f(x) = 3(x + 2)^2 - 1.

Step-by-step explanation:

f(x) = 3x² + 12x +11

f(x) = 3(x^2 + 4x) + 11        Completing the square:

f(x) =  3[(x + 2)^2 - 4] + 11

f(x) = 3(x + 2)^2 -+3*-4 + 11

f(x) = 3(x + 2)^2  - 12 + 11

f(x) = 3(x + 2)^2 - 1.

6 0
3 years ago
A concession stand at a baseball game sells 3 apples for $2.00. How can you find the cost for 10 apples? A. x=320 B. x=302 C. x=
marta [7]

Step-by-step explanation:

In order to solve this question we use ratio and proportion

From the question

3 apples were sold for $2.00

Then

10 apples will be sold for what

That's

<h2>\frac{10 \times 2}{3}  \\  =  \frac{20}{3}</h2>

Hope this helps you

4 0
3 years ago
Which answer correctly estimates the product of 79.623 × 4.83?
mamaluj [8]
The answer to this is 384.57909
6 0
3 years ago
Factor completely. x2−5x−36 Enter your answer in the box.
Kamila [148]

Answer:

(x - 9)(x + 4)

Step-by-step explanation:

x^2−5x−36

As you know, -36 = -9 * 4 and (-9) + 4 = -5

so Factor

= (x - 9)(x + 4)

4 0
3 years ago
Read 2 more answers
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
2 years ago
Read 2 more answers
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