The answer should be the first quarter moon
Answer:
C. It is a male with atleast one dominant allele
Explanation:
In the given pedigree, the two normal parents of the generation I have one daughter with the attached earlobe. Since the trait is recessive, the daughter should be homozygous recessive to express the trait. The genotype of the daughter (shaded circle in generation II) is "aa". To have a daughter with "aa" genotype, both the parents should have one copy of "a" allele. So, the genotype of both parents is "Aa".
In generation II, individual A is non-shaded square. Squares represent males in a pedigree. Since its not shaded, it does not have attached earlobe. Both the parents are heterozygous dominant for attached earlobes (Aa x Aa = 1/4 AA : 1/2 Aa : 1/4 aa). The genotype of this individual may be AA or Aa.
Answer:
Absolute Zero
Explanation:
It is based on molecular motion, with the temperature of 0K, also known as absolute zero, being the point where all molecular motion ceases. The freezing point of water on the Kelvin scale is 273.15K, while the boiling point is 373.15K
It wouldn't be 0 degrees C or 0 degrees F because the temp of the molecular motion stop in Celsius is -273.15 degrees and in Fahrenheit it would be -459.67 degrees.
I hope this helps :)
