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exis [7]
3 years ago
12

how Long will it take a plane flying north from Miami to reach New York City 1800 km away if the average velocity of the plane i

s 940 km/h
Physics
1 answer:
alukav5142 [94]3 years ago
8 0
Answer: 1.91 hours or 1 hour and 55 minutes

Procedure:

Average speed = distance / time

=> time = distance / average speed

=> distance = 1800 km / 940 km/h = 1.91 hours

0.91 hours * 60 min / hour = 54.9 min = 55 min

=> 1 hour and 55 min.
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Tarnish is produced by a redox reaction that occurs when a metal reacts with
Dvinal [7]

Answer:

Copper atoms lose electrons to sulfur atoms

Explanation:

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6 0
3 years ago
During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxima
vova2212 [387]

Answer:

The value  F  =  0.1396 \ N

Explanation:

From the question we are told that

   The volume blood  ejected is  V  =  65 \ cm^3  = 65*10^{-6} \  m^3

    The velocity of the blood ejected is  v  = 103 \  cm/s  = \frac{103}{100} = 1.03 \ m/s

    The density of blood is  \rho = 1060 \  kg/m^3

     The heart beat is R = 59 \  bpm(beats \  per \  minute) = \frac{59}{60}= 0.9833\ bps

The average force exerted by the blood on the wall of the aorta is mathematically represented as

      F  =  2 * \rho  *  V  *  R *  v

=>    F  =  2 * 1060  *  65*10^{-6}  *  0.9833 *  1.03

=>    F  =  0.1396 \ N

8 0
3 years ago
Is the momentum of a 0.1 kg Mass moving with a velocity of 5 miles per second West
dem82 [27]
<span>Momentum equals Mass x Velocity
Mass equals 0.1kg
Velocity equals 5m/s

So the momentum has to = 0.1 x 5 = 0.5kgm/s

I hope this helped
</span>
6 0
3 years ago
Read 2 more answers
Which adaptation is likely to increase the chances of survival of an animal in a rainforest?
34kurt
Black-spotted skin coat as camouflage while stalking prey.
Survival = avoiding predators or capturing prey successfully
6 0
3 years ago
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Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the
Doss [256]

Answer:

v_{su} = 19.44 m/s

Explanation:

m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg

T=9.29x10^8\\r_{o}=1.43x10^{12}

If the sun considered as x=0 on the axis to put the center of the mass as a:

m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}

solve to r1

r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}

r_1=1.428x10^9m

Now convert to coordinates centered on the center of mass.  call the new coordinates x' and y' (we won't need y').  Now since in the sun centered coordinates the angular momentum was  

L = \frac{m_{sa}*2*pi*r_1^2}{T}

where T = orbital period

then L'(x',y') = L(x) by conservation of angular momentum.  So that means

L_{sun}=\frac{m_{sa}*2*\pi *( 2r_{o}*r_1 -r_1^2)}{T}

Since

L_{su}= m_{su}*v_{su}*r_1

then

v_{su}=\frac{m_{sa}*2*pi*(2r_{o}*r_{1}-r_{1}^2)}{T*m_{sa}*r_1}

v_{su} = 19.44 m/s

7 0
4 years ago
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