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Schach [20]
3 years ago
12

Question is in attached picture. Please Help!

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
The formula for slope is:

slope=y2-y1/x2-x1  where (x1,y1) and (x2,y2) are points on the line

In this situation we know the x values of two points, and we know the slope, so we can solve for the missing y values.

slope=-7
(11,y1) (16,y2)

Now lets plug in the information into the formula.

slope=y2-y1/x2-x1
-7=y2-y1/16-11
-7=y2-y1/5
multiply both sides by 5
-35ft=y2-y1
distances cannot be negative so lets change -35ft to a positive number
35ft=y2-y1

The vertical distance between the two points is 35feet

Answer= A) 35ft
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Computer screen is 13 inches long and 10 inches wide whats the area and perimeter of the computer screen?
lorasvet [3.4K]

Answer:

130 square inches.

Step-by-step explanation:

13*10=130

7 0
3 years ago
Bob is six years older than his sister, and the sum of their ages is 32. how old is bob?/search?q=david+is+38+years+old+and+his+
erica [24]
Bob's age is 22
And her sisters age is 14
If you'll add 22&14 the answer would be 36
And if you'll subtract 22&14 the answer would be 6
4 0
3 years ago
Help plz I will giv brainliest if it's right
hjlf

Answer:

What does it say.

I can't see the photo at all !

Step-by-step explanation:

6 0
3 years ago
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
3 years ago
Read 2 more answers
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Wewaii [24]

it is 8 or  10. multiply the 10d by 11 0r 12. 13 or 14



8 0
3 years ago
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