Answer:
did you try google ? I usally search up things when I dont usally know i dont know to be honest try to search it up if you already did then good luck I hope someone answers
Hypothenus = sqrt ((x^2 - y^2)^2 + (2xy)^2) = sqrt(x^4 - 2x^2y^2 + y^4 + 4x^2y^2) = sqrt(x^4 + 2x^2y^2 + y^4) = sqrt(x^2 + y^2)^2 = x^2 + y^2
Answer:
the area of the parallelogram = base times the height
For the given parallelogram :
x = 8 units, y = 13 units, and h = 11 units
1) If x is the perpendicular to h
So, the base = 8 and the height = 11
So, the area = 8 * 11 = 88 square units
2) If y is the perpendicular to h
So, the base = 13 and the height = 11
So, the area = 13 * 11 = 143 square units
Step-by-step explanation:
First use PEMDAS so 26x2=52
52-3=49
4+49=53
53x4
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
