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3 years ago

7

A litter of pigs is born. Three are female and three are male. Which set of symbols correctly describes the gender of each pigle

t? AA X,X,X,Y,Y,Y

2 answers:

Andreas93 [3]3 years ago

6 0

Answer:

The female are represented as XX, XX, XX.

The male are represented as XY, XY, XY

Explanation:

Th female sex chromosome is represented as XX.

The male sex chromosome is represented as XY.

From the question given above, there are three female and three male.

The female are represented as XX, XX, XX.

The male are represented as XY, XY, XY

arlik [135]3 years ago

4 0

XX is female and X,Y is male so the answer is
XX, XY, XX, XY, XY, XX

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A sample of neon has a volume of 40.81 m3 at 23.5C. At what temperature, in Kelvins, would the gas occupy 50.00 cubic meters? As

mezya [45]

At $\fbox{\begin \\363 K \end{minispace}}$ temperature, a sample of neon gas will occupy $50.00 \text{ m}^{3}$ volume.

Further Explanation:

The given problem is based on the concept of Charles’ law. Charles’ law states that “at constant pressure and fixed mass the volume occupied an ideal gas is directly proportional to the Kelvin temperature.”

Mathematically the law can be expressed as,

$\fbox{ \begin \\ V \propto T \end{minispace}}$

Or,

$\frac{V}{T}=k$

Here, <em>V</em> is the volume of the gas, <em>T</em> is Kelvin temperature, and <em>k</em> is proportionality constant.

Given information:

The initial volume of neon gas is $40.81 \text{ m}^{3}$ .

The final volume of neon gas is $50.00 \text{ m}^{3}$ .

The initial temperature value is $23.5 \text{ } ^{\circ} \text{C}$ .

To calculate:

The final temperature

Given Condition:

The pressure is constant.

Mass of gas is fixed.

Solution:

Step 1: Modify the mathematical expression for Charles’ law for two different temperature and volume values as follows:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

Here,

$V_{1}$ is the initial volume of the gas.

$V_{2}$ is the final volume of the gas.

$T_{1}$ is the initial temperature of the gas.

$T_{2}$ is the final temperature of the gas.

Step 2: Rearrange equation (2) for .

$\fbox {\begin \\T_{2}=\frac{(V_{2}) \times (T_{1})}{V_{1}}\\\end{minispace}}$ …… (2)

Step 3: Convert the given temperature from degree Celsius to Kelvin.

The conversion factor to convert degree Celsius to Kelvin is,

$T(\text{K}) = T(^{\circ}\text{C}) + 273.15$ …… (3)

Substitute $23.5\text{ }^{\circ} \text{C}$ for $T(^{\circ}\text{C})$ in equation (3) to convert temperature from degree Celsius to Kelvin.

$T(\text{K}) = 23.5 \text{ } ^{\circ} \text{C} + 273.15\\T(\text{K})= 296.65 \text{ K}$

Step 4: Substitute $40.81 \text{ m}^{3}$ for $V_{1}$ , $50.00 \text{ m}^{3}$ for $V_{2}$ and $296.65 \text{ K}$ for $T_{1}$ in equation (2) and calculate the value of $T_{2}$ .

$T_{2}=\frac{(50.00 \text{ m}^{3}) \times (296.65 \text{ K})}{40.81 \text{ m}^{3}}\\T_{2}=363.45 \text{ K}\\T_{2} \approx 363 \text{ K}$

Important note:

The temperature must be in Kelvin.

The condition of fixed mass and fixed pressure must be fulfilled in order to apply Charles’ law.

Learn More:

1. Gas laws brainly.com/question/1403211

2. Application of Charles’ law brainly.com/question/7434588

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: States of matter

Keywords: neon, volume, occupies, temperature, Kelvin, degree Celsius, Charle’s law, constant pressure, fixed mass, 40.81 m^3 , 50.00 m^3 , 23.5 degree C , celsius , 363 K , sates of matter, initial volume, final volume, initial temperature, final temperature, V1 , V2 , T1 , T2 .

5 0

3 years ago

Read 2 more answers

What type of rock commonly often contains gas bubbles and the mineral(s) hornblende, muscovite, olivine, lucite, and/or plagiocl

olga_2 [115]

Scoria

Explanation:

Scoria is a rock that is commonly made up of gas bubbles and minerals such as hornblende, muscovite, olivine, lucite and or plagioclase.

Scoria is an extrusive igneous rock with a lot of cavities and vesicles indicating gas bubbles.

Scoria is product of basaltic magma.
It has nearly the same composition as basalt since it originates from it.
They silica deficient and very fine grained with holes in them.
The holes shows channels by which trapped gases are forcefully ejected out.
They are usually found associated with cindercone volcanoes.

learn more:

Volcanoes brainly.com/question/5055821

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4 years ago

How many moles are in 288.6 grams of titanium? Round your answer to the nearest hundredth. Be sure to include units.

Shtirlitz [24]

Answer:

Raw:

Namber of mole =mass/molar mass

5 0

3 years ago

Which equations represent precipitation reactions? More than one can be chosen.

Ymorist [56]

Answer is:

A. Na₂S + FeBr₂ → 2NaBr + FeS.

B. MgSO₄ + CaCl₂ → MgCl₂ + CaSO₄.

E. AgNO₃ + NaCl → AgCl + NaNO₃.

Iron sulfide (FeS) has low solubility in water.

Calcium sulfate (CaSO₄) has low solubility in water and it will form white precipitate.

Silver chloride (AgCl) has low solubility in water and it will form white precipitate.

6 0

3 years ago

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A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6

miss Akunina [59]

Answer: The value of $K_{c}$ for this reaction is 250000.

Explanation:

The given equation is as follows.

$2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)$

$N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50$ ... (1)

$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50$ ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

$3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}$ ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

$3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}$

This equation can also be re-written as follows.

$3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI$

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

$K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000$

Thus, we can conclude that the value of $K_{c}$ for this reaction is 250000.

6 0

3 years ago