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sweet [91]
2 years ago
6

What is the percent composition of beryllium (Be) and oxide (O) in BeO? Round

Chemistry
1 answer:
Rus_ich [418]2 years ago
6 0

Answer:

\% Be=36\%\\\\\% O=64\%

Explanation:

Hello!

In this case, since the percent compositions of Be and O in beryllium oxide are computed as shown below:

\% Be=\frac{m_{Be}}{M_{BeO}} *100\%\\\\\% O=\frac{m_{O}}{M_{BeO}} *100\%

Since atomic masses are respectively 9.01 and 16.0 g/mol and the molar mass of the compound is 25.01 g/mol, the resulting percent compositions are:

\% Be=\frac{9.01}{25.01} *100\%=36\%\\\\\% O=\frac{16.0}{25.01} *100\%=64\%

Best regards!

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If a block has the mass of 15.00 grams and measurements of 5.00cm by 3.00cm by 2.00cm what is the volume of the block?
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When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is diss
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An inorganic substance with the formula BaCl2 is barium chloride. It is one of the most popular barium salts that dissolve in water. Like the majority of other water-soluble barium salts, it is white, extremely hazardous, and gives flames a yellow-green tint.

When 1 mole of bacl2 is dissolved in water it releases-8.67 kj/mil of energy. calculate h when 10.3 g of barium chloride is dissolved to make a 1.00 l solution

In water, barium chloride is very soluble (as is the case with most ionic salts). In its dissolved condition, it is known to split into barium cations and chloride anions.

Let's first determine the total amount of CL- ions.

=> When HCl dissociates, one mol will produce H+ and one mol will produce CL-. Thus, . 2 moles yields. 2 mol CL-

=> One mole of Bacl2 will dissociate into one mole of Ba2+ and two moles of CL-. Therefore, 0.1 mol will result. two moles CL-

Hence, there are mols of CL- in total.

2+.2 = .4

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Total moles of solute divided by liters of solution gives the molarity, M.

= .4/.5 = 0.8 M

As a result, 0.8 M is the molarity of CL- in solution.

To know more about Barium salts, click on the link below:

brainly.com/question/1300739

#SPJ4

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