All categories

3 years ago

What is the percent composition of beryllium (Be) and oxide (O) in BeO? Round

Chemistry

1 answer:

Rus_ich [418]3 years ago

6 0

Answer:

$\% Be=36\%\\\\\% O=64\%$

Explanation:

Hello!

In this case, since the percent compositions of Be and O in beryllium oxide are computed as shown below:

$\% Be=\frac{m_{Be}}{M_{BeO}} *100\%\\\\\% O=\frac{m_{O}}{M_{BeO}} *100\%$

Since atomic masses are respectively 9.01 and 16.0 g/mol and the molar mass of the compound is 25.01 g/mol, the resulting percent compositions are:

$\% Be=\frac{9.01}{25.01} *100\%=36\%\\\\\% O=\frac{16.0}{25.01} *100\%=64\%$

Best regards!

You might be interested in

What's 5 type of energy

Law Incorporation [45]

Kinetic Energy.

Potential Energy.

Mechanical Energy.

Chemical Energy.

Thermal Energy.

8 0

3 years ago

__HgO __Hg + __O2 what is the reaction

Gelneren [198K]

Answer:

2HgO <---- 2Hg + O2

Explanation:

8 0

3 years ago

For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i

kupik [55]

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A: $KClO_4$

This compound is formed by the combination of potassium, $K^+$ which is a metal and $ClO_4^-$ ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B: $Mg(C_2H_3O_2)_2$

This compound is formed by the combination of magnesium, $Mg^{2+}$ which is a metal and $C_2H_3O_2^{-}$ ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C: $H_2S$

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D: $Ag_2S$

This compound is formed by the combination of silver, $Ag^{+}$ which is a metal and sulfur, $S^{2-}$ which is a non-metal. Thus, it will form an ionic compound.

Option E: $N_2Cl_4$

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F: $Co(NO_3)_2$

This compound is formed by the combination of cobalt, $Co^{2+}$ which is a metal and $NO_3^{-}$ ion which is a polyatomic ion. Thus, it will form an ionic compound.

6 0

3 years ago

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0

3 years ago

Pls help I’ll mark brainliest pls pls pls

katovenus [111]

The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.

7 0

2 years ago

Read 2 more answers