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sweet [91]
3 years ago
6

What is the percent composition of beryllium (Be) and oxide (O) in BeO? Round

Chemistry
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

\% Be=36\%\\\\\% O=64\%

Explanation:

Hello!

In this case, since the percent compositions of Be and O in beryllium oxide are computed as shown below:

\% Be=\frac{m_{Be}}{M_{BeO}} *100\%\\\\\% O=\frac{m_{O}}{M_{BeO}} *100\%

Since atomic masses are respectively 9.01 and 16.0 g/mol and the molar mass of the compound is 25.01 g/mol, the resulting percent compositions are:

\% Be=\frac{9.01}{25.01} *100\%=36\%\\\\\% O=\frac{16.0}{25.01} *100\%=64\%

Best regards!

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As a child (with a mass of 35.0 kg) you take your 5.0-kg sled to Orchard Downs. If you are sliding down the hill on your sled, w
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Velocity = 3.61 m/s

<h3>Further explanation</h3>

Given

mass of child = 35 kg

mass of sled = 5 kg

Kinetic energy = 260 J

Required

velocity

Solution

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

KE = 1/2.mv²

mass of object :

= mass child + mass sled

= 35 kg + 5 kg

= 40 kg

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v²=KE : 1/2.m

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3 0
3 years ago
If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s
Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing  CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>

In mass:

0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>

Acetic acid reacts completely producing  0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>

H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>

CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = <em>14.475g H₂O</em>

<em></em>

Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0
3 years ago
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