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3 years ago

Kay buys 12 pounds of apples. Each pound cost 3$. If she gives the chaser 20$ bill, how much change will she receive

Mathematics

2 answers:

Stella [2.4K]3 years ago

8 0

Well, 12x3=36 and 36>20 so Kay wouldn't have enough to pay the chaser (whatever a chaser is)

Sergeeva-Olga [200]3 years ago

4 0

12x3 is 36 so she wouldn't have the money to pay for the apples

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HELP ASAP!!! DUE IMMEDIATELY!!!

Setler [38]

Answer:

Angle ABD is 16 degrees and Angle DBC is 74 degrees

Step-by-step explanation:

Question 6. x+9+11x-3=90. 12x+6=90 -6 on both sides and 12x=84 divide each side by 12 and x= 7 angle ABD is x+9 so 7 +9= 16. Angle measure of ABD is 16 degrees. Measure of angle DBC is 11x -3 so 11 times 7=77. 77-3= 74. So the measure of angle DBC is 74 degrees and this answer is right because they both add up to be 90 degrees. Hope this helped! :)

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2 years ago

George is comparing two different phones. The screen of phone A has a width of 5.3 cm. The width of the screen on phone B

bija089 [108]

Answer:

To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.

Let's try to use decimal. Then you need to convert phone B fraction width into decimal width. The calculation would be: 5cm + 1/3cm= 5 cm + 0.333cm= 5.333cm

From here it clear that phone B has a wider screen than phone A.

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$