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Gnesinka [82]
3 years ago
5

Please help me thanks

Mathematics
2 answers:
jek_recluse [69]3 years ago
5 0
3/5 I think is the right number because there’s 60 boys and only 36 of them have a pet.
stealth61 [152]3 years ago
3 0
3/5 because the pets move a lot
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Jasmine has taken an online boating safety course and is now completing her end-of-course exam. As she answers each question, th
dsp73

Answer:

There are 60 total questions on the course exam.

Step-by-step explanation:

Given that:

Number of questions finished by Jasmine = 12

Percentage shown on the bar = 20%

The total number of questions will be 100%, therefore, 20% of the questions are equal to 12.

Let,

x be the total number of questions on the course exam

20% of x = 12

\frac{20}{100}x=12\\0.2x=12

Dividing both sides by 0.2

\frac{0.2x}{0.2}=\frac{12}{0.2}\\x=60

Hence,

There are 60 total questions on the course exam.

8 0
2 years ago
Tim needs 3 pounds of vegetables for a vegetable soup recipe.
klio [65]

Answer:

25/12 - pounds more vegetables

Step-by-step explanation:

first we need to put these variables into like terms

36/12 - 3

8/12 - 2/3

3/12 - 1/4

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8 0
3 years ago
Write 12.4% as a decimal and simplified fraction
Gnom [1K]

Given the following question:

We are given 12.4%

undefined

6 0
1 year ago
A roll of wallpaper cost £7.85 richard buy 25 rolls of wallpaper estimate
joja [24]

Answer:

Step-by-step explanation:

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7 0
3 years ago
CALCULUS: Determine which function is a solution to the differential equation y ' − y = 0.
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C: none of these are solutions to the given equation.

• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.

• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.

The actual solution is easy to find, since this equation is separable.

<em>y'</em> - <em>y</em> = 0

d<em>y</em>/d<em>x</em> = <em>y</em>

d<em>y</em>/<em>y</em> = d<em>x</em>

∫ d<em>y</em>/<em>y</em> = ∫ d<em>x</em>

ln|<em>y</em>| = <em>x</em> + <em>C</em>

<em>y</em> = exp(<em>x</em> + <em>C </em>)

<em>y</em> = <em>C</em> exp(<em>x</em>) = <em>C</em> <em>eˣ</em>

8 0
3 years ago
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