No, they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 =c^, therefore, 7^2 +x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 =5
The answer is 5
Answer:4
Step-by-step explanation:
X^2 - 6x = 20
x^2 - 6x + 9 = 20 + 9
(x - 3)^2 = 29
x - 3 = (+-) sqrt 29
x = 3 (+-) sqrt 29
x = 3 (+-) 5.39
x = 3 + 5.39 = 8.39 <=
x = 3 - 5.39 = - 2.39 <=
Answer:
Step-by-step explanation:
Answer is C
We need to find oblique asymtotes of f(x).
Oblique asymtotes form when degree of numerator is greater than denominator.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
First we divide by
Quoetient of the above division would be oblique asymtote.
First we find the degree of numerator and denominator for f(x)
Degree of f(x) at numerator = 2
Degree of f(x) at denominator = 1
So, one oblique asymtote form.
