Answer:
d. (4,3,6,2)
Step-by-step explanation:
The list of <em>second numbers</em> of the ordered pairs is the <em>range</em>.
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The second number of the first pair is 4; the second number of the second pair is 3. The only 4-number answer choice containing these two numbers is (d). You don't even have to work the whole problem to make the proper choice.
Answer:
FALSE
Step-by-step explanation:
A random variable is a variable whose outcome depends on random criteria, such as a lottery game in which any number can be drawn randomly. That way, a randomized experiment will have random results that are not predetermined. For example, if the lottery has 80 numbers, the random variable function can achieve any result, which will depend on random criteria such as the luck of the player.
Answer:
4.4722
Step-by-step explanation:
The following table shows the 36 elements of the sample space of the experiment
![\left[\begin{array}{cccccccc}&1&2&3&4&5&6\\--&--&--&--&--&--&--\\1\;|&1&2&3&4&5&6\\2\;|&2&2&3&4&5&6\\3\;|&3&3&3&4&5&6\\4\;|&4&4&4&4&5&6\\5\;|&5&5&5&5&5&6\\6\;|&6&6&6&6&6&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccccccc%7D%261%262%263%264%265%266%5C%5C--%26--%26--%26--%26--%26--%26--%5C%5C1%5C%3B%7C%261%262%263%264%265%266%5C%5C2%5C%3B%7C%262%262%263%264%265%266%5C%5C3%5C%3B%7C%263%263%263%264%265%266%5C%5C4%5C%3B%7C%264%264%264%264%265%266%5C%5C5%5C%3B%7C%265%265%265%265%265%266%5C%5C6%5C%3B%7C%266%266%266%266%266%266%5Cend%7Barray%7D%5Cright%5D)
From this table we can compute the probabilities
:
P(X = 1) = 1/36
P(X = 2) = 3/36
P(X = 3) = 5/36
P(X = 4) = 7/36
P(X = 5) = 9/36
P(X = 6) = 11/36
So the expected value equals
1P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)+5P(X=5)+6P(X=6) =
= 1/36 + 6/36 + 15/36 + 28/36 + 45/36 + 66/36 = 161/36 =
4.4722
Answer:
5a + 5b
Step-by-step explanation:
a(5 + b) = 5a + 5b
you just multiply a to 5 and a to b.
The answers are:
P(9, 2) = 72
P(5, 5) = 120
P(7, 7) = 5040
These are examples of permutations. The problems are asking us to find the total number of ways an event can happen.
In the first case, P(9, 2), we are asked to find the ways that 2 things can be chosen out of a group of 9.
9 x 8 = 72
P(5, 5) = 5 x 4 x 3 x 2 x 1
P(7, 7) = 7 x 6 x 5 x 4 x 3 x 2 x 1
