The school needs to purchase a new refrigerator for student rewards. Lowes and Scars have the model

Is (8+√2)(8-√2) Rational or irrational no need to explain why

MA_775_DIABLO [31]

Irrational

==========%%%%%%%%++++++++

3 0

3 years ago

Nancy is making lemonade for her birthday party. She made 6 batches. Each batch of lemonade uses 24 fluid ounces of lemon juice

Goryan [66]

Answer:

Step-by-step explanation:

1 Us pint = 16 Us fluid ounces

It means that 8 pints of water would be

8 × 16 = 128 fluid ounces

Each batch of lemonade uses 24 fluid ounces of lemon juice and 8 pints of water. The total number of fluid ounces in each batch is

128 + 24 = 152 fluid ounces

Also,

1 fluid ounce = 0.125 Us cups

Therefore, the number of cups made is

152 × 0.125 = 19 cups

If each serving is 1 cup, then the number of servings that she made from each batch of lemonade is 19

servings. The number of batches made is 6. Therefore, the number of servings made altogether is

6 × 19 = 114

If her brother came and spilled half of it on the floor, then the number of servings that she have left after that for her party is

114/2 = 57 servings

7 0

2 years ago

I need answer please

weqwewe [10]

Answer:

y = -3/2x + 6

Step-by-step explanation:

Parallel lines have the same slope so slope is -3/2

Using (4,0)

y = mx + b

0 = -3/2(4) + b

0 = -6 + b

b = 6

so y = -3/2x + 6

4 0

2 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

3 years ago

The fare for a taxi cab is $2.50 per passenger and $0.75 for each mile. A group of friends has $22.00

xeze [42]

For this case we have to:

x: Let the variable representing the number of people to travel in the group

y: Let the variable representing the number of miles traveled.

If friends only have $22 then we have the following inequality:

$2.50x + 0.75y \leq22$

Now, if there are three people in the group we have that $x = 3.$

$2.50 (3) + 0.75y \leq22\\7.5 + 0.75y \leq22\\0.75y \leq22-7.5\\0.75y \leq14.5\\y\leq \frac {14.5} {0.75}\\y\leq19.33$

The taxi can travel a maximum of 19.33 miles.

On the other hand, if the group wants to travel 10 miles then we have to y = 10.

$2.50x + 0.75 (10) \leq22\\2.50x + 7.5 \leq22\\2.50x \leq22-7.5\\2.50x \leq14.5\\x\leq \frac {14.5} {2.50}\\x \leq5.8$

Thus, they could travel a maximum of 5 people.

ANswer:

$2.50x + 0.75y \leq22$

Traveling 3 people, the taxi can travel a maximum of 19.33 miles

Traveling 10 miles, a maximum of 5 people can travel

7 0

2 years ago