An exam consists of two parts, Section X and Section Y. There can be a maximum of 95 questions. There must be at least 20 more q
uestions in section Y than in Section X. Write a system of inequalities to model the number of questions in each of the two sections. Then solve the system by graphing.
1 answer:
Answer:
X + Y <= 95.
Y >= 20+ X.
Step-by-step explanation:
It is given that section X and section Y can have hardly 95 questions.
Hence either both have them has total 95 questions or less than 95 questions.
If we take X as the number of questions section X has and Y as the number of questions section Y has then X + Y <= 95.
Also it is given that Y has at least more 20 more questions than Y has. Hence Y can have 20 more question than X has or more than 20 more question than X.
That is Y >= 20+ X.
As shown in the graph the line passing through (95, 0) and (0, 95) the arrows are towards the origin because the origin satisfies the equation.
In the other line the origin that is (0, 0) does not satisfy the equation. Hence the arrows will not be towards the origin.
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Step-by-step explanation:
Okay, so...
The Median of a trapezoid is directly in the middle. For some weird mathimatical reason you won't ever need to know unless it's on an exam or you become a math major, its midsegment is the average of the top length and the bottom length.
In other words,
EF = ( BC + AD ) / 2
So for part 1, we can use that equation to find x.
- Insert known equations.
- Simplify within parentheses.
- Add.
- Divide.
- Simplify.
- Divide both sides by 2.
Part 2 is a lot easier now. All we have to do is plug in 11 for x.
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Answer:
Part I: x = 11
Part II:
- BC = 23
- AD = 26
- EF = 29