The number of unique ways is given by the number of possible
combination having distinct members.
The number of unique ways there are to arrange 4 of the 6 swimmers are <u>15 ways</u>.
Reasons:
The given parameters are;
The number of swimmers available = 6 swimmers
The number of swimmers the coach must select = 4 swimmers
Required:
The number of unique ways to arrange 4 of the 6 swimmers.
Solution:
The number of possible combination of swimmers is given as follows;

Therefore, the coach can select 4 of the 6 available swimmers in <u>15 unique ways</u>
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Answer:
- 2
Step-by-step explanation:
It's a simple rule, all you are doing is subtracting 2 every time.
Answer:
1. $60
2. 600 Calories were burned
3. D
Step-by-step explanation:
1. $75 x .20=$15
75-15=$60
2. What I started with is 200/40=5 calories burned per min
60 plus 60=120
5x120=600
3. It's the only option that has something decreasing. and there is a -5 which means it's getting subtracted or its decreasing.
Answer:
< LK
Step-by-step explanation:
The higher the angle, the bigger the opposite side, so since 123 is bigger than 114, LK is bigger than MN
Answer:
(0, -3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
6x - 5y = 15
x = y + 3
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 6(y + 3) - 5y = 15
- Distribute 6: 6y + 18 - 5y = 15
- Combine like terms: y + 18 = 15
- [Subtraction Property of Equality] Subtract 18 on both sides: y = -3
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 3
- Substitute in <em>y</em>: x = -3 + 3
- Add: x = 0