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Jet001 [13]
3 years ago
11

On a coordinate plane, the location of 3 points are: (0,6),(5,-4), and (-1,-5). Where would the fourth point need to be located

in order to form a parallelogram?
Mathematics
2 answers:
vredina [299]3 years ago
6 0

Answer:

(-6, 5)

Step-by-step explanation:

The slope of the segment from (0, 6) to (5, -4) is

m = (6--4)/(0-5) = (6+4)/(-5) = 10/(-5) = -2

The slope of the segment from (-1, -5) to (5, -4) is

m = (-5--4)/(-1-5) = (-5+4)/(-6) = (-1)/(-6) = 1/6

In order to be a parallelogram, the slopes of opposite sides must be the same.  This means the slope of the segment across from the segment with a slope of 1/6 must also have a slope of 1/6.

Working from (0, 6), to find the point with a slope of 1/6 we will work backward; going down 1 and back 6, we have (0-6, 6-1) = (-6, 5).

lilavasa [31]3 years ago
3 0
The fourth point would need to be located at,

( 5 , 7 )

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
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Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
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Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


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