9514 1404 393
Answer:
68%
Step-by-step explanation:
According to the empirical rule, 68% of the distribution lies within 1 standard deviation of the mean.
Here, the mean is 20 and the standard deviation is 5. The bounds on 1 standard deviation from the mean are 20±5 = [15, 25]. This is precisely the interval of interest.
68% of students wait between 15 and 25 minutes
Answer:
- g(x) = x^2 – 4x – 21
- g(x) = 3x^2 – 12x – 63
- g(x) = –(x + 3)(x – 7)
Step-by-step explanation:
When r is an x-intercept of the function, (x -r) is a factor. The two given x-intercepts mean that two factors of the function are (x -(-3))(x -7). There may be a vertical scale factor that is not necessarily positive.
These factors multiply out to give ...
(x +3)(x -7) = x^2 -4x -21 . . . . . . matches the first choice
When this expression is multiplied by 3, it matches the third choice:
3(x +3)(x -7) = 3x^2 -12x -63
When the factored form is multiplied by -1, it matches the fourth choice:
-(x +3)(x -7)
The answer is 22 because the 5t and -5t cancel each other
Answer:
2
Step-by-step explanation:
Jk its window
<span>Lets calculate an example:
Say, .001% of tires that come from the factory are bad. There is a 1/1000 chance that for any given tire randomly selected from the warehouse that a defect will be present. Each tire is a mutually exclusive independently occurring event in this case. The probability that a single tire will be good or bad, does not depend on how many tires are shipped in proportion to this known .001% (or 1/1000) defect rate.
To get the probability in a case like this, that all tires are good in a shipment of 100, with a factory defect rate of .001%, first divide 999/1000. We know that .999% of tires are good. Since 1/1000 is bad, 999/1000 are good. Now, multiply .999 x .999 x .999..etc until you account for every tire in the group of 100 shipped. (.999 to the hundredth power)
This gives us 0.90479214711 which rounds to about .90. or a 90% probability.
So for this example, in a shipment of 100 tires, with a .001% factory defect rate, the probability is about 90 percent that all tires will be good.
Remember, the tires are mutually exclusive and independent of each other when using something like a factory defect rate to calculate the probability that a shipment will be good.</span>
