The value you should get is 34. I'm assuming n is variable we should use. "the square of a number increased by 9" = "n^2+9" in an algebraic expression. then you plug in. 5^2+9 and then solve. 5^2=25. 25+9=34
Customers per hr.....108 (customers) / 9 (hrs) = 12 customer per hr
The given function is greater than or equal to 0 for the interval given as follows:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
<h3>When a function is positive and when it is negative?</h3>
- A function is positive when it is above the x-axis.
- A function is negative when it is below the x-axis.
For this problem, with a closed interval, we have that the function is above for:
x ≤ -3, -1 ≤ x ≤ 0, x ≥ 2.
Hence the interval notation is:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
More can be learned about functions at brainly.com/question/24808124
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Answer:
Slope = y^2 - y^1 / x^2 - x^1
Graph n1
Slope = -5 - 1 / -6 - 2
Graph n2
Slope = -5 - 3 / 3 - 5
Graph n3
Slope = 3 - 0 / -4 - 5
Answer:
A=15
B=13??
C=15
D=85
Step-by-step explanation:
B is the only one I'm not sure
