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4 years ago

Find 0.01 more than 9.154

Mathematics

1 answer:

sp2606 [1]4 years ago

5 0

Answer:

Hey!

Your answer is 9.164!!

Step-by-step explanation:

Adding 0.01 means just adding 1 to THE DIGIT IN THE HUNDRETH PLACE...2 SPACES RIGHT OF DECIMAL POINT!

5+1=6

SUB IN:

9.164

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PLEASE HELP!! ILL MARK BRAINLYEST!! Evaluate 6C2 . 120 15 720 30

AlexFokin [52]

Answer: 15

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Josie and Rushawn ran a race. Josie finished in 329 seconds. Rushawn finished less than 60 seconds later. Which inequality

Neporo4naja [7]

Answer: r < 389

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

Rushawn's possible finishing times (r) must be less (<) than Josie's finishing time (329) plus 60 seconds.

Mathematically speaking:

r < 329+60

r < 389

So, the correct option is the last one.

Feel free to ask for more if needed or if you did not understand something.

6 0

3 years ago

Need help with a math question

ludmilkaskok [199]

Answer:

There are 10 possible ways the student can schedule the three classes

Step-by-step explanation:

The college student is choosing 3 classes to take during the first, second, and third semester from 5 electives.

Therefore, the student is choosing 3 items from a total of 5 and the order is not of key concern here. This is thus a combination problem;

5C3 = 10

read as 5 choose 3

The above mathematical operation can be performed using any modern calculator.

7 0

3 years ago

If a projectile is fired with an initial speed of vo ft/s at an angle α above the horizontal, then its position after t seconds

Elena L [17]

Answer:

a) The bullet hits the ground after 64 seconds.

b) The bullet hits the ground 113,511.7 feet away.

c) The maximum height attained by the bullet is of 16,384 feet.

Step-by-step explanation:

Equations of motion:

The equations of motion for the bullet are:

$x(t) = (v_0\cos{\alpha})t$

$y(t) = (v_0\sin{\alpha})t - 16t^2$

In which $v_0$ is the initial speed and $\alpha$ is the angle.

Initial speed of 2048 ft/s at an angle of 30o to the horizontal.

This means that $v_0 = 2048, \alpha = 30$ .

$x(t) = (v_0\cos{\alpha})t = (2048\cos{30})t = 1773.62t$

$y(t) = (v_0\sin{\alpha})t - 16t^2 = (2048\sin{30})t - 16t^2 = 1024t - 16t^2$

(a) After how many seconds will the bullet hit the ground?

It hits the ground when $y(t) = 0$ . So

$1024t - 16t^2 = 0$

$16t^2 - 1024t = 0$

$16t(t - 64) = 0$

16t = 0 -> t = 0 or t - 64 = 0 -> t = 64

The bullet hits the ground after 64 seconds.

(b) How far from the gun will the bullet hit the ground?

This is the horizontal distance, that is, the x value, x(64).

$x(64) = 1773.62(64) = 113511.7$

The bullet hits the ground 113,511.7 feet away.

(c) What is the maximum height attained by the bullet?

This is the value of y when it's derivative is 0.

We have that:

$y^{\prime}(t) = 1024 - 32t$

$1024 - 32t = 0$

$32t = 1024$

$t = \frac{1024}{32} = 32$

At this instant, the height is:

$y(32) = 1024(32) - 16(32)^2 = 16384$

The maximum height attained by the bullet is of 16,384 feet.

7 0

3 years ago

HELP PLS FAST

Snezhnost [94]

Answer:

sin a=3/5

cos a=4/5

Step-by-step explanation:

sin A

AB(squared)=AC (squared)+CB(squared) AB(squared)=4(squared)+3(squared)

AB (squared)=16+9

AB (you must put a square root over AB)=25(remember 25 is now a square root)

AB=5

sin a=opposite/hypotenuse

=3/5

cos A

cos a=adjacent/hypotenuse

=4/5

8 0

3 years ago