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3 years ago

ASAP PLZ HELP ON THIS SIMPLE QUESTION!

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

You can make it 9ft long and 11ft tall. 9×11=99, between 97 and 107.

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How do you find the HCF of 15t and 6s?

earnstyle [38]

Answer:

HCF=3

Step-by-step explanation:

Factors of 15t= 3*5*t

Factors of 6s= 2*3*s

HCF= Common factors

common factor = 3

HCF=3

4 0

3 years ago

: A pack of crayon was shared between two friend Shantel and Carl in the ratio 3:5. If Shantel received 27 crayons, how many cra

Sergeeva-Olga [200]

Answer:

72 crayons

Step-by-step explanation:

8/3 × 27 = 72 crayons

3 0

3 years ago

Suppose a large shipment of telephones contained 21% defectives. If a sample of size 498 is selected, what is the probability th

grandymaker [24]

Answer:

$P(-3\% < x < 3\%) = 0.901$

Step-by-step explanation:

Given

$p = 21\%$

$n = 498$

Required

$P(-3\% < x < 3\%)$

First, we calculate the z score

$z = \sqrt{p * (1 - p)/n}$

$z = \sqrt{21\% * (1 - 21\%)/498}$

$z = \sqrt{21\% * (79\%)/498}$

$z = \sqrt{0.1659/498}$

$z = \sqrt{0.000333}$

$z = 0.0182$

So:

$P(-3\% < x < 3\%) = P(-3\%/0.0182 < z$

$P(-3\% < x < 3\%) = P(1.648 < z$

From z probability, we have:

$P(-3\% < x < 3\%) = 0.901$

6 0

3 years ago

Graphing (y=x+6) (y=-2x-3)

nignag [31]

Answer:

srry its black but thats how you would graph it

Step-by-step explanation:

8 0

3 years ago

A decibel is a logarithmic unit that can be used to measure the intensity of a sound. The function y = 10logx gives the intensit

Anna007 [38]

Answer:

The sound intensity of a whisper is 333.3 times the reference intensity

Step-by-step explanation:

Given : The function $y = 10logx$ gives the intensity of a sound in decibels, where x is the ratio of the intensity of the sound to a reference intensity.

A whisper has a sound intensity of 30 decibels.

To find : Use your graph to help you complete the following statement. The sound intensity of a whisper is times the reference intensity.

Solution :

Graph is attached which shows their intersection at (1000,30).

We can also verify by substituting value.

We have given that a whisper has a sound intensity of 30 decibels.

Therefore, y=30 , Let log base 10

$y = 10logx$

$30 = 10logx$

$\frac{30}{10} =logx$

$3=logx$

Logarithmic property $log_{x}b=a \Rightarrow b=x^a$

$x=10^3$

$x=1000$

The ratio of the intensity of the sound to a reference intensity is 1000 decibels

The sound intensity of a whisper is times the reference intensity is

$\frac{1000}{3}=333.33$

The sound intensity of a whisper is 333.3 times the reference intensity.

7 0

3 years ago

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