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Rama09 [41]
3 years ago
5

A pair of shoes at Nordstrom’s costs $120. The shoes are on sale for 15% off. You have a coupon that allows you take an addition

al 10% off. How much will the shoes cost?
Mathematics
1 answer:
ycow [4]3 years ago
4 0

okay so you multiply .15 by 120 which is 18. then you multiply .10 by 120 which is 12. so you do 120 subtracted by 12 and 18 which the answer is 90

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Bharat has two identical ink pens with full ink. He used 3/4th of the ink from the first pen and 2/3rd of the ink from the secon
Leno4ka [110]

Answer:

0.58333333333 Or 0.58333333333/100000000000

Step-by-step explanation:

3 0
3 years ago
The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 fe
r-ruslan [8.4K]

Answer:

AB=131\ ft

Step-by-step explanation:

we know that

The perimeter of the rectangular lot is

P=2(AB+BC) ----> equation A

where

AB is the length

BC is the width

we have

AB=2BC-1 ---> equation B

P=394\ ft ----> equation C

substitute equation B and equation C in equation A

394=2(2BC-1+BC)

solve for BC

394=2(3BC-1)

394=6BC-2

6BC=396

BC=66\ ft

<em>Find the value of AB</em>

AB=2BC-1

AB=2(66)-1

AB=131\ ft

6 0
3 years ago
Simplify the expression. Write your answer as a power.
OlgaM077 [116]
59049/1048576 the / is a fraction
8 0
3 years ago
How are 12 fl oz equivalent to 335 ml
Mazyrski [523]
The question asks us to find that 12 fl oz is equivalent to 335 ml. Then we have to either convert the milliliter to oz or vice-verse. In this case we will convert 12 fl oz to milleter and check if it comes to 335 ml.
Now we already know that
1 oz = 29.57 ml
Then
12 oz = (29.57 * 12) ml
          = 354.84 ml
         = 355 ml
So we see that 12 oz is not equal to 335 ml but it is almost equivalent to 335 ml.
4 0
3 years ago
D/d{cosec^-1(1+x²/2x)} is equal to​
SIZIF [17.4K]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

Let assume that

\rm :\longmapsto\:y =  {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

We know,

\boxed{\tt{  {cosec}^{ - 1}x =  {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}

So, using this, we get

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 +  {x}^{2} } \bigg)

Now, we use Method of Substitution, So we substitute

\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z =  {tan}^{ - 1}x}

So, above expression can be rewritten as

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 +  {tan}^{2} z} \bigg)

\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)

\rm\implies \:y = 2z

\bf\implies \:y = 2 {tan}^{ - 1}x

So,

\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x

Thus,

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)

\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)

\rm \:  =  \: 2 \times \dfrac{1}{1 +  {x}^{2} }

\rm \:  =  \: \dfrac{2}{1 +  {x}^{2} }

<u>Hence, </u>

\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) =  \frac{2}{1 +  {x}^{2} }}}}

<u>Hence, Option (d) is </u><u>correct.</u>

6 0
2 years ago
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