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-Dominant- [34]
3 years ago
13

A self-confident person knows that:

Computers and Technology
1 answer:
Ganezh [65]3 years ago
3 0
It’s c for sure because it the only one making more since
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The first documented use of work release was in the ____.
sattari [20]
I'd say in the United States.

This United States penological practice was inaugurated in 1913 by state senator Henry Huber. Typically, under the work release program, a prisoner who is sufficiently trusted  is employed outside the jail during working hours and returns to confinement at the end of the shift.



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Do the pros of interpersonal communication via social media outweigh the cons? Explain.
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To find resources on the Internet for your courses, you may need to use a search engine. Suppose that you are collecting informa
tekilochka [14]

Answer:

d. "Columbus, Wisconsin"

Explanation:

mark me brainliest please

8 0
3 years ago
Hard disk works on the following technologies: (i) Technology used within the hard drive to read & write data to the drive a
Alex787 [66]

Answer:

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Explanation:

8 0
3 years ago
write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
3 years ago
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