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3 years ago

The first step to accurate coding is to identify the ___________ in the diagnostic statement.

Computers and Technology

1 answer:

jeka943 years ago

5 0

Answer: Main term

Explanation:

The first step and main step of the accurate coding is to identify the main term in diagnostic statement, that are typically find in the medical records of the patient.

The programmer while coding the data locating main term in the front of the data that is index. So, it make easy to analysis the given statement.

Main term included any type of diseases, alphabets and symptoms which is important to highlight.

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When internet techonology was developed in the 1970s by the department of defense?

Scorpion4ik [409]

TRUE. The internet began as a military infrastructure project for communication purposes.

3 0

3 years ago

Consider the code below. Note that the catch statements in the code are not implemented, but you will not need those details. As

Dmitriy789 [7]

Missing Part of Question

An exception raised by the instruction in i3 would be caught by the catch statement labeled?

Answer:

e3 and e4.

Explanation:

The instruction tag i3 points to the following code segment

a[++i] = (double) (1 / x); // i3

The code segment above performs arithmetic operation (double)(1/x)

And then assigns the value of the arithmetic operations to an array element a[++I]

It's possible to have one or both of the following two exceptions.

1. Error in Arithmetic Operation

2. Index of Array out of bound

These are both represented in exception tags e3 and e4

catch (ArithmeticException ex) {...} // e3

catch (ArrayIndexOutOfBounds ex) {...} // e4

Exception e3 can arise when the program try to carry out invalid arithmetic operation.

For instance, 1/0 or 0/0.

This will lead to ArithmeticException to be thrown

Exception e4 can arise when the program tries to assign values to an index that's not in an array.

Say, the total index in a given array a is 5.

The index of this array is 0 to 4; i.e. a[0] to a[4]

The moment the program tries to assign values to array element other than the ones I listed above (e.g a[5]) ArrayIndexOutOfBounds exception will be thrown

6 0

3 years ago

Use the modulo operator (%) to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which

uranmaximum [27]

Hi, you haven't provided the programing language in which you need the code, I'll just explain how to do it using Python, and you can apply a similar method for any programming language.

Answer:

def rightMost(num):

lenNum = len(str(num))

rightNum = num%(10**(lenNum-1))

print(rightNum)

return(rightNum)

Explanation:

In this function we receive an integer number, then we find how many digits this number has, and finally, we find the rightmost digits; the main operation is modulo (takes the remainder after a division), what we want is to take all the digits except the first one, for that reason we find the modulo of the number when divided by ten to the power of the length of the number minus one, for example, if the number is 2734 we divided by 10^(4-1), where four is the length of the number, this way we get 2734/1000 and the module of it is 734.

5 0

3 years ago

What Is an Antivirus?

wariber [46]

Antivirus software, or anti-virus software, also known as anti-malware, is a computer program used to prevent, detect, and remove malware. Antivirus software was originally developed to detect and remove computer viruses, hence the name.

8 0

3 years ago

Read 2 more answers

Programming challenge description: Write a program that, given two binary numbers represented as strings, prints their sum in bi

Lubov Fominskaja [6]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //include header file

using namespace std;

string add(string a, string b) //define add function

{ //declare variable

string result = "";

int sum = 0,k,l;

cahr x;

k= a.size() - 1;

l = b.size() - 1;

while (k>= 0 || l>= 0 || sum == 1) //loop

{

//addition

sum= sum+ ((k >= 0)? a[k] - '0': 0);

sum= sum+ ((l >= 0)? b[l] - '0': 0);

x=sum%2;

result=(x+'0') +result;

// Compute carry

sum =sum/ 2;

// Move to next digits

k--;

l--;

}

return result; //return value

}

int main() //main method

{

string a,b; //string variable

cout<<"Enter first binary digit: "; //message.

cin>>a; //input from user

cout<<"Enter Second binary digit: "; //message.

cin>>b; //input from user

cout <<"Addition :"<<add(a, b)<<endl; //print addition

return 0;

}

Output:

Enter first binary digit: 1101

Enter Second binary digit: 100

Addition :10001

Explanation:

In the above c++ program first, we include the header file. Then we define the add function in the add function we add two binary digits by passing value as arguments. In this function, we define a variable that is used on the addition of binary numbers. In this function we define the loop in the loop we check if two binary number is 1 then it will print 0 and pass 1 as the carry. after performing addition it will return value. In the main function, we take two binary numbers from the user and pass the value to the function and print function return value.

8 0

4 years ago