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3 years ago

180=2x+y which equation is used to find x

Mathematics

1 answer:

Serggg [28]3 years ago

3 0

180=2x+y
180-y=2x
(180-y)/2=x

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A lawn in the shape of a trapezoid has an area of 1,800 square meters. The length of one base is 50 meters, and the length of th

Alona [7]

9514 1404 393

Answer:

40 m

Step-by-step explanation:

The area is given by the formula ...

A = 1/2(b1 +b2)h

Using the given values, we can find h to be ...

1800 = 1/2(50 +40)h

3600 = 90h . . . . . . . . . multiply by 2

40 = h . . . . . . . . . . . divide by 90

The width of the lawn is 40 meters.

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3 years ago

A certain star is 2.4 x 102 light years from the Earth. One light year is about 5.9 x 1012 miles. How far

Studentka2010 [4]

Answer:

2.5 x $10^{15}$ miles

Step-by-step explanation:

We are given that 1 light year ≈ 5.9 x $10^{12}$ miles so:

4.3 x 10² light year · <u>5.9 x </u> $10^{12}$ <u> miles </u>
1 light year

Multiply 4.3 an 5.9 and round to 2 significant digits then add the exponents:

≈25 x $10^{14}$

This is not the scientific notation since the number is not between 0 and 10 so we move the decimal point by 1 place to the left. We then add 1 to the exponent to obtain the final answer:

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6 0

2 years ago

What are 2 factors of 72y + 108z?

emmasim [6.3K]

72y+108z Factored is 36(2y+3z). So I guess the 2 factors will be 2y and 3z??

7 0

3 years ago

PLEASE HHELP!!! Bring the fraction:

Anna35 [415]

Answer:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

Step-by-step explanation:

Given

$\frac{b}{7a^2c}$

Express the denominator as $35a^3c^3$

To do this, we divide $35a^3c^3$ by the denominator

$\frac{35a^3c^3}{7a^2c} = 5ac^2$

So, the required fraction is:

$\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}$

$\frac{5abc^2}{35a^3c^3}$

Hence:

$\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}$

Given

$\frac{a}{a - 4}$

Express the denominator as $16 - a^2$

Multiply the fraction a+4/a+4

So, we have:

$\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}$

Apply difference of two squares to the denominator

$\frac{a^2 + 4a}{a^2 - 16}$

Take the additive inverse of the numerator and denominator

$\frac{-(a^2 + 4a)}{-(a^2 - 16)}$

$\frac{-a^2 - 4a}{16 -a^2}$

Hence:

$\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}$

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2 years ago

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professor190 [17]

Answer:

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Step-by-step explanation:

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2 years ago