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3 years ago

lemon looked at 26 Web sites in 39 minutes. at that rate, how many Web sites would she look at in 12 minutes?

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

26 sites in 39 minutes

26/39 = 0.667

0.667 x 12 = 8

8 sites in 12 minutes

nignag [31]3 years ago

6 0

8 websites in 12 minutes

Hope this helped :)

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Select the points you need to calculate the average rate of change from the beginning of the

sammy [17]

It would be the points (0,80) and (15,10)

6 0

3 years ago

Read 2 more answers

According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist

Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of birth weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(birth weight under 6.3 pounds)

P(x < 6.3)

$P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < -1) = 0.159 = 15.9\%$

15.9% of babies are born with birth weight under 6.3 pounds.

8 0

2 years ago

Caroline wants to buy a pair of shoes that has an original price of $40.00. She has a coupon for a 30% discount off of the origi

fredd [130]

Answer:
$26.32

step-by-step explanation:
it originally was $40.00
she has a coupon for 30%
30% of 40.00 is 12
40 • 0.30 = 12
40 - 12
$28
it is now $28 after the coupon
her state charges an 6% sales tax on the discounted price
6% of 28 is 1.68
28 • 0.06 = 1.68
28 - 1.68 = 26.32

6 0

2 years ago

Find the range of possible values for the following measurements, which were rounded to the nearest mm, tenth of m, and hundredt

zmey [24]

The required range of the data is 24mm

The range of data is the difference between the largest value and the least value in a set of data.

Since we are not given the range of data. Let's assume we gave the following data:

34mm, 30mm, 20mm, 44mm, 31mm

From the data

Highest measurement = 44mm

Least measurement = 20mm

Find the range

Range = Highest measurement - Least measurement

Range = 44mm - 20mm

Range = 24mm

Hence the required range of data is 24mm

<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>

<em>Learn more here: brainly.com/question/1786006</em>

6 0

2 years ago

The Internal Revenue Service (IRS) provides a toll-free help line for taxpayers to call in and get answers to questions as they

sukhopar [10]

Answer:

From the result of the one-tailed z-test, we can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Step-by-step explanation:

Sample size = 50

Mean waiting time = 13 minutes

Standard deviation = 11 minutes

We need to perform one hypothesis test that the actual mean waiting time turned out to be significantly less than the 15-minute claim made by the taxpayer advocate.

The null hypothesis would be that there is no significant difference.

H₀: μ₀ = 15 minutes

The alternative hypothesis would be that the mean waiting time is indeed significantly less than the 15-minute claim by the taxpayer advocate.

Hₐ: μ₀ < 15 minutes.

This is evidently a one tail hypothesis test (we're investigating only in one direction; less than the claim). Hence, we can use the z-test

z = (x - μ)/σₓ

σₓ = (σ/√n) = (11/√50) = 1.556

z = (13 - 15)/1.556 = - 1.29

Using the z-table at significance level of 0.05.

p-value = 1 - 0.9115 (from the z-tables)

p-value = 0.0885

Since the p-value is more than the significance level (0.0885 > 0.05), we do not reject the null hypothesis.

Hence, we accept the null hypothesis and can conclude that the mean waiting time is not significantly less than the the 15 minute claim by the taxpayer advocate.

Hope this Helps!!!

4 0

3 years ago