Solve this inequality: 3b – 7 < 32

2 answers:

7 0

Hello! So for this question, we need to get the number with the variable by itself. First, let's add 7 to cancel out -7. Add 7 to 32 to get 39. Then, we get 3b < 39. Now, divide each side by 3 to isolate the b. 39/3 is 13. There. b < 13. The answer is B.

gulaghasi [49]3 years ago

4 0

The answer is B, because if it were 13, the equation would be 39-7<32, which is not true, so it is less than 13, and therefore the answer is B.

You might be interested in

v = 20.8x^2 - 458.3x + 3,500 represents the value of a car from 1964 to 2002. What year did the car have the least value? (x= 0

Karo-lina-s [1.5K]

See the picture for all detail, I have done it by hand.
Few important steps;
-Take the first derivative
-Put it equal to zero
-you get the x value which is equal to 11
-Now for the check that x=11 is the least value or not, take the second derivative
-As, the 2nd derivative is positive so it is the least value

As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value

7 0

4 years ago

Dhalia rolls a number cube that has sides labeled 1 to 6 and then flips a coin what is the probability that she rolls an even nu

Tanya [424]

Probability = 1/4, or 25%
The probability of rolling an even number on a die: 1/2
(1, 2, 3, 4, 5, 6; 3 are even numbers, 3/6 = 1/2)

The probability of flipping heads: 1/2
(heads or tails)

1/2 x 1/2 = 1/4

3 0

3 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.