Answer:
24 minutes.
Step-by-step explanation:
This question shows up in a great many places in math or physics, so it is a pretty good question to learn how to do.
First you should note that answer will be under 40 minutes.
1/40 + 1/60 = 1/TimeTotal
The common denominator on the left is 120 minutes
3/40*3 + 2/60*2 = 1/timetotal
3/120 + 2/120 = 1/ timetotal
5/120 = 1/time total Now to use to the key stop
What you do now is you always turn the left side over. You do the same thing to total time.
120/5 = total time
24 = total time
What this means is that if you let both pipes run for 24 minutes, they will fill the tank working together.
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
Answer:
Either 130 or 131 would be acceptable.
Step-by-step explanation:
When we estimate, we do not use exact values.
66.17 is close to 66
44.98 is close to 45
20.15 is close to 20
Add the estimates together: 66+ 45+ 20 = 131
We could also estimate 66.17 to 65 which would give us an estimate of 130
Answer:
C
Step-by-step explanation:
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80p=pr^2+p(2r)^2
80p=pr^2+4pr^2
80=r^2+4r^2
80=5r^2
16=r^2
r=4 for the smaller circle´s radius, and 8 is the larger circle´s radius.
Have a nice day, I hope this was helpful :D
