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Tresset [83]
3 years ago
5

Find the missing value

Mathematics
1 answer:
taurus [48]3 years ago
4 0

Answer: P=$7,1333.33

Step-by-step explanation:

Equation: P=A/(1+rt)

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Kierston needs to paint a wall of the youth center. She knows that 1 can of paint covers an area of 2.2 square meters. Kierston
Step2247 [10]

Answer:

See Explanation

Step-by-step explanation:

Given

1\ can = 2.2m^2

Required

Determine the number of cans for the wall

The dimension of the wall is not given. So, I will use the following assumed values:

Length=20m

Width = 44m

First, calculate the area of the wall

Area = Length * Width

Area = 20m * 44m

Area = 880m^2

If 1\ can = 2.2m^2

Then x = 880m^2

Cross Multiply:

x * 2.2m^2 = 1 * 880m^2

x * 2.2m^2 = 880m^2

x * 2.2 = 880

Make x the subject

x = \frac{880}{2.2}

x = 400

400 cans using the assume dimensions.

So, all you need to to is, get the original values and follow the same steps

4 0
3 years ago
Margo borrows $1100, agreeing to pay it back with 8% annual interest after 9 months. How much simple
Leokris [45]

Answer: I wrote the answer in docs so here is the pic for the whole equation i explained it too! I hope this helped

7 0
3 years ago
Find the area of the shaded region in square units. Show your reasoning.
motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side l, so, the area unit is l^2

the diagonal's square is l\sqrt{2}

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2

CALCULATION OF MAIN SQUARE AREA

A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2

TOTAL AREA

A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2

3 0
3 years ago
A ship leaves port and travels due west for 30 knots, then changes course to S 30° W and travels 50 more knots. Find the bearing
leva [86]

Answer:

  232°

Step-by-step explanation:

There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.

  30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))

  = (0, -30) +(-43.301, -25) = (-43.301, -55)

Then the angle from port is ...

  arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle

The bearing of the ship from port is about 232°.

_____

<em>Comment on the problem statement</em>

The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.

5 0
3 years ago
C. Solve for the missing measurements. <br>m&lt;AZL<br> m AL<br><br>​
Margaret [11]
AZL is the correct answer
5 0
3 years ago
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