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dolphi86 [110]
3 years ago
12

After x – 2y = 8 is put in slope-intercept form, what are the slope and y-intercept?

Mathematics
1 answer:
baherus [9]3 years ago
6 0

the slope is 1 and the y intercept is-2

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Can someone please help!! I'll give brainliest for 30 points!! Please help!
a_sh-v [17]
The area of the trapezoid can be found by adding the two right triangles formed on the ends and the rectangular section in between.

1) Is 42 square inches

2) is 13 square inches

The area of a hexagon can be found by finding the inscribed trapezoid and multiplying by 2.

3) is 552 inches squared
6 0
3 years ago
If f(x) = 2x+6 find the value of h if f(h) =4
Volgvan

Answer:

18

Step-by-step explanation:

f(x) is the ultimate base of all function notation forms

f(h) is the addition of 4(Vertical Shift of 4)

f(h)=2x+10

If f(4), then 2(4)+10

f(4)=18

4 0
2 years ago
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Alina [70]

Answer:

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 28.983051

Chi-square value = χ² = 2.154239

Degree of freedom = 1

Critical value = 3.841

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

Step-by-step explanation:

He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.

So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Data collected by Dr. Pagels:

                                              meadow voles     common voles      Row Total

apple slices                                     26                          32                      58

peanut butter-oatmeal                   35                          25                     60

Column Total                                   61                          57                     118

Where 118 is the grand total.

The expected number is given by

Expected = (row total)×(column total)/grand total

Expected meadow vole/apple slices = 58×61/118

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 58×57/118

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 60×61/118

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 60×57/118

Expected common vole/peanut butter-oatmeal = 28.983051

The chi-square statistic value is given by

χ² = Σ(Observed - Expected)²/Expected

χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051

χ² = 2.154239

The degrees of freedom is given by

DoF = (row - 1)×(col - 1)

For the given case, we have 2 rows and 2 columns

DoF = (2 - 1)×(2 - 1)

DoF = 1

The given level of significance = 0.05

The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be

Critical value = 3.841

Conclusion:

Reject H₀ If χ² > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

For the given case,

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

8 0
3 years ago
Craig and Alissa are building a sandcastle on the beach. They each have a bucket. Craig's bucket holds 1/2 pound of sand and Ali
Nitella [24]
<h3>Amount of sand craig and Alissa collect together at one time is 1.4 pounds</h3>

<em><u>Solution:</u></em>

Given that,

Craig and Alissa are building a sandcastle on the beach. They each have a bucket

Craig's bucket holds 1/2 pound of sand and Alissa's bucket holds 9/10 pound of sand

Therefore,

Craig\ bucket = \frac{1}{2}\ pound\\\\Alissa\ bucket = \frac{9}{10}\ pound

<em><u>How much sand can craig Alissa collect together at one time</u></em>

Add both, we get

Collect\ together = \frac{1}{2} + \frac{9}{10}\\\\Collect\ together = \frac{1 \times 5}{2 \times 5} + \frac{9}{10}\\\\Collect\ together = \frac{5}{10} + \frac{9}{10}\\\\Collect\ together = \frac{9+5}{10}\\\\Collect\ together = \frac{14}{10} = \frac{7}{5} = 1.4\\\\In\ mixed\ fractions,\\\\Collect\ together = 1\frac{2}{5}

Thus, amount of sand craig and Alissa collect together at one time is 1.4 pounds

4 0
3 years ago
I dont really understand this
galina1969 [7]

Answer:

1. a^-b

2.a^b/a^c

3.a^c/b^c

4 0
3 years ago
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