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3241004551 [841]
3 years ago
11

For what value of x does 25x=5x2-3?

Mathematics
2 answers:
Leokris [45]3 years ago
3 0
I might be wrong but I'll give it a shot, you subtract the 5x from the right side and put it on the left with makes it 20x=2-3. Then subtract the 3 from the 2 which makes it 20x=-1. So it would be -0.05.

I'm not 100% sure. But his is my guess.
Savatey [412]3 years ago
3 0
Important:  Use " ^ " to indicate exponentiation:  <span>25x=5x^2-3.

Rearrange these terms in descending powers of x:  5x^2 - 25x - 3 = 0

This is a quadratic equation.  To solve it, you could use a graphing calculator, the quadratic formula, completing the square or other approaches.

</span>Let's complete the square of 5x^2 - 25x - 3 = 0:

5(x^2 - 5x)                        = 3
5(x^2 - 5x + 25/4 - 25/4)   = 3
5(x-5/2)^2    - 125/4          = 3 = 12/4
5(x-5/2)^2                         =137/4
  (x-5/2)^2     -25/4           = 137/20
  (x -5/2)^2                        = 125/20+137/20 = 162/20= 81/10
Taking the sqrt of both sides, we get:

  x-5/2                               = plus or minus 9/sqrt(10)
Then:

x = 5/2 plus or minus 9sqrt(10) / 10, or
x = 25/10 plus or minus 9sqrt(10)/10, or

       25 plus or minus 9sqrt(10)
x = -------------------------------------
                      10
                    
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Answer:

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y=5x-1=4

Step-by-step explanation:

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Which of the following is equivalent to 2 ln e^ln 5x = 2 ln 15?
neonofarm [45]

Answer:

x  = 3

Step-by-step explanation:

Given in the question an equation,

2lne^{ln5x}=2ln15

Step 1

e^{lnx}=x

so,

2ln(5x)=2ln15

Step 2

cancel 2 on both sides of the equation

ln{5x}=ln15

Step 3

ln{5x}-ln15=0

ln\frac{5x}{15}=0

Step 4

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Step 5

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8 0
3 years ago
Explain how you know which method you should use to solve a rational equation.
notsponge [240]

<u>Methods to solve rational equation:</u>

Rational equation:

A rational equation is an equation containing at least one rational expression.

Method 1:

The method for solving rational equations is to rewrite the rational expressions in terms of a common denominator. Then, since we know the numerators are equal, we can solve for the variable.

For example,

\frac{1}{2}=\frac{x}{2}\Rightarrow x=1

This can be used for rational equations with polynomials too.

For example,

\frac{1+x}{x-3}=\frac{4}{x-3}\Rightarrow(1+x)=4 \Rightarrow x=3

When the terms in a rational equation have unlike denominators, solving the equation will be as follows

\frac{x+2}{8}=\frac{3}{4}

\Rightarrow\frac{x+2}{1}=\frac{3\times8}{4}\Rightarrow{x+2}=2\times3

\Rightarrow{x+2}=6\Rightarrow x=6-2\Rightarrow x=4

Method 2:

Another way of solving the above equation is by finding least common denominator (LCD)

\frac{x+2}{8}=\frac{3}{4}

Factors of 4: 1\times2\times2

Factors of 8: 1\times2\times2\times2

The LCD of 4 and 8 is 8. So, we have to make the right hand side denominator as 8. This is done by the following step,

\Rightarrow\frac{x+2}{8}=\frac{3}{4}\times{2}{2}

we get,

\Rightarrow\frac{x+2}{8}=\frac{6}{8}

On cancelling 8 on both sides we get,

\Rightarrow(x+2)=6\rightarrow x=6-2\rightarrow x=4

Hence, these are the ways to solve a rational equation.

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