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3 years ago

For what value of x does 25x=5x2-3?

2 answers:

3 0

I might be wrong but I'll give it a shot, you subtract the 5x from the right side and put it on the left with makes it 20x=2-3. Then subtract the 3 from the 2 which makes it 20x=-1. So it would be -0.05.

I'm not 100% sure. But his is my guess.

Savatey [412]3 years ago

3 0

Important: Use " ^ " to indicate exponentiation: <span>25x=5x^2-3.

Rearrange these terms in descending powers of x: 5x^2 - 25x - 3 = 0

This is a quadratic equation. To solve it, you could use a graphing calculator, the quadratic formula, completing the square or other approaches.

</span>Let's complete the square of 5x^2 - 25x - 3 = 0:

5(x^2 - 5x) = 3
5(x^2 - 5x + 25/4 - 25/4) = 3
5(x-5/2)^2 - 125/4 = 3 = 12/4
5(x-5/2)^2 =137/4
(x-5/2)^2 -25/4 = 137/20
(x -5/2)^2 = 125/20+137/20 = 162/20= 81/10
Taking the sqrt of both sides, we get:

x-5/2 = plus or minus 9/sqrt(10)
Then:

x = 5/2 plus or minus 9sqrt(10) / 10, or
x = 25/10 plus or minus 9sqrt(10)/10, or

25 plus or minus 9sqrt(10)
x = -------------------------------------
10

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3 years ago

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7 0

3 years ago

How do you do: -6(6a-5)=-2(8-5a)

devlian [24]

Answer:

a = 1

Step-by-step explanation:

1. distribute the -6 on the left into the parentheses. you should get -36a + 30.

2. on the side right of the =, distribute the -2 to get -16 + 10a.

now it should look like -36a + 30 = -16 + 10a.

3. move the terms over to isolate the a value. subtract 30 to the right side to get -46 (-36a=-46+10a)

4. move the 10a on the right to the left by subtracting it to the other side.

(-46a=-46)

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3 years ago

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1 year ago

If f(x) = 3x + 2, what is f(5)?

iVinArrow [24]

Hi there!

$\large\boxed{f(5) = 17}}$

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To find f(5), we simply substitute in 5 for x:

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f(5) = 15 + 2

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3 years ago