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Tpy6a [65]
3 years ago
9

Debbie has two stocks, X and Y. Consider the following events:

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

The correct answer is (D)

Step-by-step explanation:

Given the events X and Y:

X = the price of stock X has increased

Y = the price of stock Y has increased

That means that the complement of these events are:

X' = the price of stock X has not increased

Y' = the price of stock Y has not increased

Hence, the event "the price of stock X has increased and the price of stock Y has not increased" may be written as:

X ∩ Y′

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Given y=log3(x+4) what is the domain
Luden [163]
As you know, the domain is the values "x" can safely take on.

well, for a logarithmic expression, it can never have an expression of 0, namely in this case, x + 4 must never be 0, since such a logarithm doesn't exist.

now, x + 4 = 0 ---> x = -4.

thus if "x" ever becomes -4, we'd end up with log₃(-4+4), or log₃(0), which is a no dice.

so the domain is all values except -4.
5 0
3 years ago
Read 2 more answers
2 hundredths + 6 hundredths = ________ hundredths?
IRISSAK [1]

Answer:

8 hundredths

Step-by-step explanation:

2 + 6 = 8

8 0
3 years ago
3. A map pencil drawer contains the following colors: 5 Purple, 3 Yellow,
natta225 [31]
Add up all the numbers together
it’ll give you 17
since they’re asking abt the probability of a purple being chosen twice, multiply 5 by 2 to give you 10
so 10/17
3 0
3 years ago
Evaluate (2-3)^(4) - 9 = 3.<br> 0-7<br> 0-2<br> 0 1<br> 02
EleoNora [17]

Answer:

Step-by-step explanation:

(2-3)⁴ *4 - 9 + 3 = (-1)⁴ *4 - 9 + 3

                          = 1*4 - 9 +3

                          = 4 - 9 + 3

                          = - 5 + 3

                           = - 2

6 0
2 years ago
Read 2 more answers
I need help thank you
IRISSAK [1]

Answer:

1) k = 3

2) 3, 4, 5

3) k + (k + 2) + (k + 4) = 4k

4) 6, 8, 10

Step-by-step explanation:

Jared used the equation;

k + (k + 1) + (k + 2) = 4k

Let's find k.

3k + 3 = 4k

4k - 3k = 3

k = 3

Thus,the integers will be;

3, (3 + 1) and (3 + 2)

This is; 3, 4, 5

He is looking for consecutive even integers but yet got 3 and 5 which are odd numbers. However, he should have used the format;

k, (k + 2), (k + 4) as the 3 consecutive even integers.

Thus, rewriting the main equation gives;

k + k + 2 + k + 4 = 4k

3k + 6 = 4k

4k - 3k = 6

k = 6

Thus,the integers are;

6, (6 + 2), (6 + 4)

This is; 6, 8, 10

6 0
3 years ago
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