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Liula [17]
3 years ago
11

Whats the definition of nuts cells

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

A nut is a fruit composed of an inedible hard shell and a seed, which is generally edible. In general usage and in a culinary sense, a wide variety of dried seeds are called nuts, but in a botanical context "nut" implies that the shell does not open to release the seed (indehiscent). The translation of "nut" in certain languages frequently requires paraphrases, as the word is ambiguous.

Nataliya [291]3 years ago
7 0
Nut, in botany, dry hard fruit that does not split open at maturity to release its single seed. A nut resembles an achene but develops from more than one carpel (female reproductive structure), often is larger, and has a tough woody wall. Examples of true nuts are the chestnut, hazelnut, and acorn.
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Convert.<br>5 days =<br>lao<br>hours​
Andreas93 [3]

Answer:

120 Hours

Step-by-step explanation:

24 hours in a day

5 days

24 x 5 = 120

8 0
3 years ago
5a+5b+5c=-20<br> 4a+3b+3c=-6<br> -4a+3b+3c=9
tekilochka [14]
For 5a+5b+5c=-20

A= -4 - b - c

B= -4 - a - c

C= -4 - a - b

———————————

4a+3b+3c=-6

A= -3/2 - 3b/4 - 3c/4

B= -2 - 4a/3 - c

C= -2 - 4a/3 - b

———————————

-4a+3b+3c=9

A= -9/4 + 3b/4 + 3c/4

B= 3 + 4a/3 - c

C= 3 + 4a/3 - b
4 0
3 years ago
Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq
AnnyKZ [126]

Answer:

(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the function

                    f(x) = e^{4x} \sqrt{1+e^{2x} }

Now integrating on both sides, we get

                 \int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx

                               =    \int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx

                         

<u><em>Step(ii):-</em></u>

  Let  1 + e^{2x}  = t

           e^{2x}  = t -1  

          2e^{2x}dx = d t

          e^{2x}dx = \frac{1}{2} d t

                = \int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx

                  = \int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }

                 = \frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }

                = \frac{1}{2} \int\limits {(t^{\frac{1}{2}  } t^{1} +t^{\frac{1}{2} } ) } \, dx

                = \frac{1}{2} \int\limits {(t^{\frac{3}{2}  } +t^{\frac{1}{2} } ) } \, dx

               = \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C

              =  \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C

             = \frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C

            = (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

<u><em>Final answer:-</em></u>

= (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

             

3 0
3 years ago
Evaluate.<br><img src="https://tex.z-dn.net/?f=%20-%20%20%5Csqrt%7B81%7D%20" id="TexFormula1" title=" - \sqrt{81} " alt=" - \s
loris [4]

Answer:

Step-by-step explanation:

First find factors of 81

3 81

3 27

3 9

3 3

1

81 = 3×3×3×3

81 = 3^4

Taking squareroot

∴ -√81 = -√3^4

= -3^2

= -9

5 0
3 years ago
Evaluate the expression c<img src="https://tex.z-dn.net/?f=a%5E%7B2%7D" id="TexFormula1" title="a^{2}" alt="a^{2}" align="absmid
never [62]

ca^2+a

= -2×5^2+5

= -2×25+5

= -50+5

= -45....

4 0
2 years ago
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