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2 years ago

9

Solve the equation. Select all that apply.

1 answer:

nika2105 [10]2 years ago

4 0

Answer:

x = 11, x = -11

Step-by-step explanation:

I know this is kind of late but the two previous answers were wrong.

We have x² = 121. To find x, we need to get rid of the exponent, and to do this, we can take the square root of both sides:

√x² = √121

x = √121

You might think that x = 11 but remember, x can be negative as well because you can square negative numbers. Basically, every real number has two square roots - a positive and a negative one. So, the answer isn't just x = 11, it's also x = -11 because (-11)² = 121 as well.

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Find the area of the shaded region. Round your answer to the nearest tenth if needed.<br><br> 4B

AlexFokin [52]

Answer:

136.1 inches

Step-by-step explanation:

area of a circle is r^2 x pi

this is 3/4 of a circle

1. so 3/4 x 7.6^2xpi

2. 3/4 x 57.76 x pi

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2 years ago

6. Which statement about this figure is true?

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2 years ago

Find the x intercept and y intercept for 6x-2y=18 . provide an explanation and show steps

allochka39001 [22]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Find the length of the following curve. If you have a grapher, you may want to graph the curve to see what it looks like.

stepladder [879]

The length of the curve $y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

$y = \frac{1}{27}(9x^2 + 6)^\frac 32$ from x = 3 to x = 6

Start by differentiating the curve function

$y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x$

Evaluate

$y' = x(9x^2 + 6)^\frac 12$

The length of the curve is calculated using:

$L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx$

This gives

$L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx$

Expand

$L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx$

This gives

$L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx$

Express as a perfect square

$L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx$

Evaluate the exponent

$L =\int\limits^6_3 {3x^2 + 1} \ dx$

Differentiate

$L = x^3 + x|\limits^6_3$

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

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1 year ago

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Answer:

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2 years ago

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