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Leokris [45]
2 years ago
9

Solve the equation. Select all that apply.

Mathematics
1 answer:
nika2105 [10]2 years ago
4 0

Answer:

x = 11, x = -11

Step-by-step explanation:

I know this is kind of late but the two previous answers were wrong.

We have x² = 121. To find x, we need to get rid of the exponent, and to do this, we can take the square root of both sides:

√x² = √121

x = √121

You might think that x = 11 but remember, x can be negative as well because you can square negative numbers. Basically, every real number has two square roots - a positive and a negative one. So, the answer isn't just x = 11, it's also x = -11 because (-11)² = 121 as well.

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allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

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2 years ago
Simplify the radical expression below.<br><br><img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B7%7D%20-%20%5Csqrt%7B63%7D%20" id=
anzhelika [568]

So for this, we can simplify √63 as such:


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Using the simplified version of √63, we can solve it:


3\sqrt{7} -3\sqrt{7} =0


Zero is your final answer.

4 0
3 years ago
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