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Inessa05 [86]
2 years ago
5

HELPPP PLEASEEE !!! John draws AABD, with CD as the perpendicular bisector of AB such that AACD and ABCD are congruent to each o

ther.
DO
Which statement can John use this figure to prove?
Every isosceles triangle is a right triangle.
The base angles of any triangle are congruent.
The points on the perpendicular bisector of a side of a triangle are equidistant from all of the vertices of the triangle.
The points on the perpendicular bisector of a side of a triangle are equidistant from the vertices of the side it bisects.

Mathematics
1 answer:
laila [671]2 years ago
4 0

Answer:

The points on the perpendicular bisector of a side of a triangle are equidistant from the vertices of the side it bisects.

Step-by-step explanation:

It is the last option. The perpendicular bisector theorem states that if  a point lies on  the bisector of a segment it is equidistant from the endpoints.

Meaning

If a perpendicular bisector is a line of the side of the triangle , it bisects the sides forming two right angles .

The first three choices are incorrect because

1) the figure shows a triangle bisected into two triangles and option 1 tells about 1 isosceles triangle.

2) The base angles of any triangle can be different or same .

3) the three perpendicular bisectors meet at a point called the circumeter. We have 1 perpendicual bisector which is dividing the triangle into two equal triangles.

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A triangular sail has a base length of 2.5 centimeters. The area of the sail is 3.75 square meters. How tall is the sail?
seraphim [82]

The area of any triangle = (1/2) x (length of the base) x (height)

2.5 centimeters  =  0.025 meter

The area of the sail is           (3.75) = (0.5) x (0.025) x (height)

Multiply each side by  2 :      (7.5) =            (0.025) x (height)

Divide each side by  0.025 :  (7.5)/(0.025) = height  =<em>  300 meters</em>

The situation is stupid, but the math is bullet-proof.


6 0
3 years ago
Help please it is graphing
Alja [10]

Here are the pairs:

(from the left)

First group: 3rd graph, y = x - 2, table g

Second group: 2nd graph, y = 2x, table b

Third group: 1st graph, y = x + 2, table m

4 0
3 years ago
Find the common ratio of the geometric sequence-15,-30,-60
blondinia [14]

Answer:

2

Step-by-step explanation:

The common ratio of the sequence is 2 because between each term you are multiplying by 2 to get the next term

7 0
3 years ago
What is the answer to this
Arisa [49]

Answer:

x = 20, <S = 47 degrees, <P = 131 degrees

Step-by-step explanation:

27 + x + 119 + 63 + 3x + 71 = 360

4x + 280 = 360

4x = 80

x = 20

<S = 27 + x = 27 + 20 = 47 degrees

<P =  3x + 71 = 3(20) + 71 = 131 degrees

5 0
3 years ago
Choose the midpoint of the line segment with endpoints at (5, 9) and (11, 15).
Tcecarenko [31]

Answer:

C) (8,12)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2} )(\frac{y_1+y_2}{2} )\\MP= (\frac{5+11}{2} )(\frac{9+15}{2} )\\MP= (\frac{16}{2} )(\frac{24}{2} )\\MP= (8,12)

8 0
3 years ago
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