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3 years ago

Can someone please answer this ASAP it’s a quiz and I need to get a good grade on it I will give you five stars

Mathematics

1 answer:

sp2606 [1]3 years ago

5 0

(A^2 + B^2 = C^2) —> (1600 + 39,204 = 40,804) —-> (square root 40,804) the answers is {{202}}

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

Help me please i’m so far behind and i’m trying to finish before summer ends im freaking out

frozen [14]

The correct answer is 5
Solve for x by simplifying both sides of the equation, then isolating the variable.
X=5

3 0

3 years ago

Read 2 more answers

The sum of three consecutive integers is 261 , which equation could be used to find the integer .

Allisa [31]

Answer:

You got it wrong, its the first option

Step-by-step explanation:

Since its not asking for a consectuive EVEN or ODD integer its not

X + X+2 + X+4...

Instead its just the normal way

X + X+1 + X+2 + X+3....

SO thats the correct answer.

4 0

3 years ago

73590 rounded to the nearest thousand

11Alexandr11 [23.1K]

Okay, so here is a small lesson on rounding. When you round you MUST know the place value of each number. Ones, tens, hundreds, thousands, millions.
So, when we look at this number what do we have in the ones place --there is a 0 -- in the tens place we have a 9 and in the the thousands place we have 5. to round this number look at the tens place. if the number is greater than 5 you round 73590 to 73600, if it is 4 and lower it stays the same and the numbers behind change to zero--> like so 73500. But for this problem it would round up to 73600.

5 0

3 years ago

A class is collecting aluminum cans. Every Monday each student brings in a bag with 10 cans. They put 10 bags into a box. How ma

yan [13]

Answer:

the answer is 100.

Step-by-step explanation:

divide 1000 by 10

5 0

2 years ago