1) Determine the horizontal force, Fx, exerted by the block on Usain
cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N
2) Determine the Impulse of that force on Usain.
I = F*t = 1597.48N * 0.32s = 511.19 N*s
3) Determine change in momentum of Usain, Δp
Δp = I = 511.19 N*s
4) Find change if velocity
Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s
Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s
Answer: 5.94 m/s
The answer is 19
First you must set up the equation
÷
First, you must make the mixed number a improper fraction
÷
Then you must divide

Finally, simplify
19
Answer:
Step-by-step explanation:
let sum of zeros=s
and product of zeros=p
then quadratic equation is x²-sx+p=0
x²-(-1/2)x+(-3)=0
x²+1/2 x-3=0
2x²+x-6=0
Slope equals rise over the run
so if slope = 5 then the rise also equals 5 and the run is 1