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disa [49]
3 years ago
5

Roshan has 18 crackers he shares the crackers equally with his brother then roshan eats 3 crackers how many crackers does toshan

have left
Mathematics
2 answers:
ruslelena [56]3 years ago
8 0
Youd have 6 crackers left after roshan eats 3 of rhem
aleksklad [387]3 years ago
4 0

Answer:

He has 6 crackers left

Step-by-step explanation:

18 and you split it by 2 to get 9 then you subtract 3 from 9

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Can you solve for y plz
vredina [299]
Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
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8 0
3 years ago
PLEASE HELP!! Ill mark the brainliest!!!!
ira [324]

Answer:

x = 5√2

y = 5√6

z = 5√3

ΔABC ~ ΔBDC ~ ΔADB

Step-by-step explanation:

ΔABC, ΔBDC, and ΔADB are all similar triangles to each other.

By definition of similar triangles, the corresponding sides have the same ratios.

CD from ΔBDC corresponds to BD from ΔADB, and BD from ΔBDC corresponds to AD from ΔADB. So:

CD / BD = BD / AD

10 / x = x / 5

x² = 50

x = 5√2

Since ΔBDC is right, we can use the Pythagorean Theorem to solve for y:

CD² + BD² = BC²

10² + (5√2)² = y²

y² = 100 + 50 = 150

y = 5√6

Again, since ΔΔABD is right, we can use the Pythagorean Theorem to solve for z:

AD² + BD² = AB²

5² + (5√2)² = z²

z² = 25 + 50 = 75

z = 5√3

3 0
4 years ago
Read 2 more answers
To graph the inequality x > -3, draw an open circle on -3 and shade to the left.
dedylja [7]
False, you graph an open circle on -3 and shade to the right because x must be larger than -3 and it can not equal -3
8 0
2 years ago
Please solve it 90 POINTS please help- PLEASE HELP its Identify the following for the quadratic relations please slove it all pl
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Answer:

\boxed{\mathrm{view \: explanation}}

Step-by-step explanation:

2)

a) elimination method

b) substitution method

c) substitution method

For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.

For the second part we can substitute y as 2x+5 in the second equation and solve for x.

For the third part we can substitute y as 4x+3 in the first equation and solve for x.

3)

\boxed{\mathrm{view \: attachment}}

8 0
3 years ago
Which method do you prefer to use to find sums- count by tens and ones, use compatible numbers, or use friendly numbers and adju
Usimov [2.4K]

I prefer to use compatible numbers because by using this method it is easier to make a sum mentally. This is true because compatible numbers are close in value to the actual numbers. For a better understanding, let's take an example:


Suppose you have two numbers, namely 640 and 40. These two numbers are compatible for division because:


64 ÷ 4 = 16


So, we have used mental arithmetic to solve a more complex problem.

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3 years ago
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