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3 years ago

Heeeeeeeeeeeeeeeeeeeeeeeeelp

Mathematics

2 answers:

zlopas [31]3 years ago

5 0

Answer:

C &A

Step-by-step explanation:

Just by analyzing the problem you can match up the answers

Solve the problem in your head and the closest answer to that is the answer

makkiz [27]3 years ago

4 0

Answer:

B and D are equivalent to -3.75+2(-4x+6.1)-3.25x

Step-by-step explanation:

The initial equation is -11.25x+8.45

A is equivalent to 5x+8.1

B is equivalent to 8.45-11.25x

C is equivalent to -7.25x+4.35

D is equivalent to -11.25x+8.45

Hope this helps! Please mark as brainliest!! <3

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If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

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3 years ago

A scale drawing of a garden uses a scale that is 1 inch = 4 feet. If the garden is 12 feet in length how long will it be on the

lesantik [10]

Answer:

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Step-by-step explanation:

We can use proportions to solve. Put the map on top and the real life size on bottom.

1 inch x inches

------------- = -------------

4 ft 12 ft

Using cross products

1 * 12 = 4 * x

Divide each side by 4

12/4 = 4x/4

3 =x

3 inches

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3 years ago

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You answered 14 questions correctly on a 15-question quiz. what percent did you receive on the quiz?

Ira Lisetskai [31]

Answer:

93.3

Step-by-step explanation:

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3 years ago

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LuckyWell [14K]

Answer:

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Step-by-step explanation:

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2 years ago

Solve using DISTANCE = RATE X TIME

wariber [46]

The rate is speed which 50m/h. so he left the home at 10:00 and arrived at noon which 12:00pm so the difference is 2 hours which means he took 2 hours to get there.
to find the distance.
D=RxT = 50 x 2 = 100mile

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3 years ago

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