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2 years ago

7

if a committee of 4 is to be chosen at random from the class of 11 students what is the probability of any particular commuter b

eing selected. (fraction form)

1 answer:

Darina [25.2K]2 years ago

7 0

i think the answer is 4/11 because the 4 people has a 1% chance out of the 11 people

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What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^

Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1

2(w2 − 2w) = 5 Expand (undo the brackets),

and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

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2 years ago

Rewrite each of the following durations using eighth notes. Write in words and as a fraction: 1 quarter note 1 half note 1 full

LenKa [72]

Answer: one third. one half and 1 whole

Step-by-step explanation:

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3 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

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3 years ago

-2(g+4)+7g<br><br><br> A. 5g - 8<br><br> B. 9g + 8<br><br><br> I’d appreciate if someone helped me:)

Yuki888 [10]

Answer:

A. 5 g - 8 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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2 years ago

(6t^4-t+1) - (6t^3-4t)

goldenfox [79]

Answer:

$= 6 {t}^{4} - 6 {t}^{3} + 3t + 1$

Step-by-step explanation:

$6 {t}^{4} - t + 1 - 6 {t}^{3} + 4t \\ = 6 {t}^{4} - 6 {t}^{3} + 3t + 1$

5 0

2 years ago