Answer: x=8
Step-by-step explanation:
Since we are given that ∠ABC and ∠DBC are complementary angles, we know that adding them together should give us 90°. We can use this to solve for x.
6x+13+4x-3=90 [combine like terms]
10x+10=90 [subtract both sides by 10]
10x=80 [divide both sides by 10]
x=8
Now, we know that x=8.
Answer:
24 cm squared
44 cm squared
66 cm squared
Step-by-step explanation:
6(4)= 24
11(4)= 44
11(6)= 66
Answer:
Length of AB = 6 cm
Length of the segment BC = 14 cm
Step-by-step explanation:
Here, B is a point on a segment AC.
AB : BC = 3:7
Length of the segment AC = 20 cm
Now, let the common ratio between the segment is x.
So, the length of AB = 3 x , and Length of BC = 7 x
Now, AB + BC = AC
⇒ 3x + 7x = 20
or, 10 x = 20
or, x = 2
Hence, the length of AB = 3 x = 3 x 2 = 6 cm
and the length of the segment BC = 7x = 7 x 2 = 14 cm
Answering:
188
Explaining:
To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.
After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.
Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.
Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.
