1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mylen [45]
4 years ago
15

How to solve? -21w(w-26)

Mathematics
1 answer:
Lady_Fox [76]4 years ago
4 0
You Multiply Using The Distributive Property
−21w2+546w
You might be interested in
A gym teacher orders 16 dodgeballs. each case contains 4 dodgeballs. which of the following equations represents the number c of
DaniilM [7]
4c=16
4 in each container and you're working out how much containers (c) you need for 16 dodgeballs, so 4c=16 
7 0
3 years ago
Very easy; answer asap, 18 points
AnnZ [28]

The second post is wrong.

The third post is also wrong.

The fifth post is also wrong.


558 is the number of dollars made in revenue. Assuming each student payed the same, you actually can find out the price that each student payed, which is 4.50.


8 0
3 years ago
What is 528,492 rounded to the nearest thousand?
Yanka [14]

Answer: 528,000

Step-by-step explanation: 492 is less then 500 so...

7 0
3 years ago
The population of a local species of bees can be found using an infinite geometric series where a1=860 and the common ratio is 1
erma4kov [3.2K]
a_1=860
a_2=\dfrac{a_1}5
a_3=\dfrac{a_2}5=\dfrac{a_1}{5^2}
\vdots
a_n=\dfrac{a_{n-1}}5=\dfrac{a_{n-2}}{5^2}=\cdots=\dfrac{a_1}{5^{n-1}}

The kth partial sum is

\displaystyle S_k=\sum_{n=1}^ka_n=\sum_{n=1}^k\frac{a_1}{5^{n-1}}
S_k=a_1\left(1+\dfrac15+\dfrac1{5^2}+\cdots+\dfrac1{5^{k-2}}+\dfrac1{5^{k-1}}
\dfrac15S_k=a_1\left(\dfrac15+\dfrac1{5^2}+\dfrac1{5^3}+\cdots+\dfrac1{5^{k-1}}+\dfrac1{5^k}\right)

\implies S_k-\dfrac15S_k=a_1\left(1-\dfrac1{5^k}\right)
\dfrac45 S_k=860\left(1-\dfrac1{5^k}\right)
S_k=1075-\dfrac{1075}{5^k}

As k\to\infty, we're left with

\displaystyle\sum_{n=1}^\infty a_n=\lim_{k\to\infty}\left(1075-\frac{1075}{5^k}\right)=1075

which is the upper limit to the population of the bees.
4 0
3 years ago
F(x)=x^2+10<br><br> Over which interval does fff have a positive average rate of change?
ohaa [14]

Answer:

(0, inf)

Step-by-step explanation:

The average rate of change of a function is related to it's first derivative. When the first derivative is positive, the average rate of change is positive, which means that the function is crescent.

Now, when the first derivative is negative, the average rate of change will be negative too, and the function is going to be decrescent.

In your function.

We have: f'(x) = 2x

2x > 0 when x > 0. So when x > 0 the average rate of change of your function is positive, and it's values increases as the time increases. When x < 0, the average rate of change is negative, so, as the time increases, the values of f decrease.

You can use a graphic tool to plot f and visualize this better.

6 0
3 years ago
Read 2 more answers
Other questions:
  • HELP ME PLEASE!!!!
    11·1 answer
  • What is Y=-9x+11 in point slope form
    15·1 answer
  • A store window shows 2 red caps and 8 greens caps. What percentage of the caps are red?
    8·2 answers
  • Which steps should be followed to write an equivalent ratio to find 2% of 6700? Write 2% as the ratio StartFraction 200 Over 100
    7·1 answer
  • How do you find an area?
    11·2 answers
  • Determine the equation of the line that passes through the indicated point
    14·1 answer
  • Cow gives two fifths of liters of milk each day. How many liters of milk can the cow give in the second month of 2016?
    6·1 answer
  • Jim and three friends shared 2 poster boards for an art project. What part of the construction paper will each friend get? *
    11·1 answer
  • Akira sells 217 homemade candles. She charges $29 for each candle. How much money does Akira make on these candles in all?
    12·1 answer
  • Can someone solve this and explain it in steps to someone that have never learned this?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!