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2 years ago

Graph. Y + 1 = 1/3 ( x - 3)

Mathematics

1 answer:

zvonat [6]2 years ago

6 0

Answer:

y=1/3x-2

Step-by-step explanation:

Plot a point at x=-2 and then for the slope (1/3, rise/run) count up 1 and over 3 starting from -2. This is a line. Y intercept at -2 and x intercept at 6.

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If 115% of a number is 460, what is 75% of that number?

Bond [772]

Answer:

300

Step-by-step explanation:

Step 1:

460/115 = x/75 Equation

Step 2:

115x = 34,500 Multiply

Step 3:

x = 34,500 ÷ 115 Divide

Answer:

x = 300

Hope This Helps :)

8 0

2 years ago

Someone help me with this

qwelly [4]

Answer:

Step-by-step explanation:

there are 9 digits.

and round it off to the nearest hundred million which is 3.

There are 8 digits before the 3... so 10 gets to the power of 8.___ 10⁸

3,0×10⁸ m.s^-1

3 0

2 years ago

Please help me answer it

jeka94

Answer:

i dont know toooo pls answer it fast......................................

Step-by-step explanation:

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3 0

2 years ago

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of the line that passes through (−12, 15) and (4, −5) is

$m_{1} = \frac{ - 5 - 15}{4 - - 12}$

$m_{1} = \frac{ - 20}{16} = - \frac{5}{4}$

The slope of the line going through (−8, −9) and (16, 21) is

$m_{2} = \frac{21 - - 9}{16 - - 8}$

$m_{2} = \frac{21 + 9}{16 + 8}$

$m_{2} = \frac{30}{24} = \frac{5}{4}$

The product of the two slopes is

$m_{1} \times m_{2} = - \frac{4}{5} \times \frac{5}{4} = - 1$

Since

$m_{1} \times m_{2} = - 1$

the two lines are perpendicular.

4 0

3 years ago

Read 2 more answers

What is the volume of this container?

Keith_Richards [23]

Answer:

The volume of the container is $56\ in^{3}$

Step-by-step explanation:

we know that

The volume of the figure is equal to

$V=Bh$

where

B is the area of the base

h is the height of the figure

Let

$h=4\ in$

Find the area of the base B

$B=(4*4)-(1*2)=14\ in^{2}$

substitute

$V=14*4=56\ in^{3}$

3 0

3 years ago