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Sloan [31]
2 years ago
9

What are the like terms in the expression 7y + 4 +4x + 7​

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
7 0

Answer:

4, 7

Step-by-step explanation:

7y + 4 +4x + 7​

The only like terms are the constants 4 and 7

7y is like yogurt and 4x is like xrays, we don't  mix them

nlexa [21]2 years ago
6 0
Like terms are terms with the same variable, or no variable. The like terms are 4 and 7. 4x and 7y can not be added to anything else in this expression because they don’t have the same variable. Hope this helped!!
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I don't know how to solve this. help please?
iragen [17]

Answer:

51   74

Step-by-step explanation:

x = smaller

x +23 = larger

added together   (x   + x+23)    equal to 28 less than 3x      = 3x-28

x    + x+23  = 3x-28      subtract 2x from both sides of the equation

   23 = x -28      add 28 to both sides

 51 = x      then the larger   =  51 + 23 = 74

8 0
2 years ago
Read 2 more answers
Mrs. Santos is buying binders for the students in her class. She determined that 15 binders would cost $22.50.
Eva8 [605]

Answer:

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6 0
2 years ago
The world's population has grown at an average rate of 1.9 percent per year since 1945. There were approximately 4 billion peopl
kkurt [141]

Answer:  f(t) = 4000000000( 1 .019)^t

Step-by-step explanation:

Here, According to the question,  The population of the world is 4 billion (approx).

Again According to the question, The world's population has grown at an average rate of 1.9 percent per year since 1945.

Therefore, after 1975 the growth rate will remains same.

Thus, the population of the world after t years,

f(t) = 4000000000( 1+\frac{1.9}{100} )^t   (By the formula A = P(1+\frac{r}{100})^t )

⇒f(t) = 4000000000( 1.019 )^t

Where 1.019 is the growth rate and 4 billion is the initial population.


6 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
Factor p^4-81 completely showing all work.
3241004551 [841]

Answer:

Step-by-step explanation:

p^4-81=(p^2)^2-9^2=(p^2+9)(p^2-9)=(p^2-9(-1))(p+3)(p-3)\\=(p^2-9i^2)(p+3)(p-3)\\=(p+3i)(p-3i)(p+3)(p-3)

8 0
3 years ago
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