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Sloan [31]
2 years ago
9

What are the like terms in the expression 7y + 4 +4x + 7​

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
7 0

Answer:

4, 7

Step-by-step explanation:

7y + 4 +4x + 7​

The only like terms are the constants 4 and 7

7y is like yogurt and 4x is like xrays, we don't  mix them

nlexa [21]2 years ago
6 0
Like terms are terms with the same variable, or no variable. The like terms are 4 and 7. 4x and 7y can not be added to anything else in this expression because they don’t have the same variable. Hope this helped!!
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Write and solve an equation based on the following question.
Ket [755]

Answer:

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Step-by-step explanation:

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5 0
1 year ago
Please help. I really don't seem to understand this question. ​
ivann1987 [24]

Answer:

m3=15(8)+22=142

m1=19(8)-10=142

Both are equal so the answer is Yes they are parallel

3 0
2 years ago
What is the Midpoint of segment BC with B(-9, -4) and C(-3, 5)?<br>​
Anastasy [175]

Answer:

(-6,0.5)

Step-by-step explanation:

(-9 + -3)÷2= -6

(-4 + 5)÷2=0.5

(-6,0.5)

3 0
2 years ago
WILL MARK BRAINLIEST The amount (A) that principal (P) will be worth after t years at interest rate (r) compounded annually is
alex41 [277]

Answer:

15 years

Step-by-step explanation:

Since we're looking for time, we can use the formula t =  A / Pr, which would be:
t = 6000/(7255 x 5.5%)
Converting the percentage into decimal form
t = 6000/(7255 x 0.055)
We can then solve to get:
t = 6000/399.025
t = 15.03665183...
Meaning it would take 15 years for an interest of 5.5% on $6,000 to reach $7,255. Not very worth $1,255 extra if you need that 6k for rent.

4 0
2 years ago
a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long
QveST [7]

Answer:

10.1 years.

Step-by-step explanation:

It is given that,

Principal = 9000

Rate of interest = 5%

No. of times interest compounded = 2 times in an year

Amount after certain time = 14800

The formula for amount:

A=P(1+\frac{r}{n})^{nt}

where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.

Substitute the given values in the above formula.

14800=9000(1+\frac{0.05}{2})^{2t}

\frac{14800}{9000}=(1+0.025)^{2t}

1.644=(1.025)^{2t}

Taking log both sides.

\log(1.644)=\log(1.025)^{2t}

\log(1.644)=2t\log(1.025)    [\because \log a^b=b\log a]

\frac{\log(1.644)}{2\log(1.025)}=t

t=10.066

t=10.1

Therefore, the required time is 10.1 years.

3 0
3 years ago
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