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3 years ago

What is the area of the circle?

Mathematics

2 answers:

Tanzania [10]3 years ago

6 0

Area = $\pi$ * r^2
= $\pi$ * 1.8^2
= 10.1787602m^2

Natasha_Volkova [10]3 years ago

4 0

A = PI * (r)^2

A = PI * (1.8)^2

A = ~3.14 * 3.24

A = <span>10.1787601976</span>

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jolli1 [7]

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5 0

3 years ago

Read 2 more answers

5 more than 3 times a variable, x, is 23

Monica [59]

3x + 5 = 23

5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23

(you add 5 to 3x)

If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:

3x + 5 = 23 Subtract 5 on both sides

3x + 5 - 5 = 23 - 5

3x = 18 Divide 3 on both sides to get "x" by itself

$\frac{3x}{3} =\frac{18}{3}$

x = 6

5 0

3 years ago

To solve the equation 5sin(2x)=3cosx, you should rewrite it as___.

galina1969 [7]

Answer:

Step-by-step explanation:

We want to solve the equation:

$5\sin(2x)=3\cos(x)$

To do so, we can rewrite the equation.

Recall the double-angle for sine:

$\sin(2x)=2\sin(x)\cos(x)$

By substitution:

$5\left(2\sin(x)\cos(x)\right)=3\cos(x)$

Distribute:

$10\sin(x)\cos(x)=3\cos(x)$

We can subtract 3cos(x) from both sides:

$10\sin(x)\cos(x)-3\cos(x)=0$

And factor:

$\cos(x)\left(10\sin(x)-3\right)=0$

Hence, our answer is A.

*It is important to note that we should not divide both sides by cos(x) to acquire 10sin(x) = 3. This is because we need to find the values of x, and one or more may result in cos(x) = 0, and we cannot divide by 0. Hence, we should subtract and then factor.

5 0

2 years ago

Read 2 more answers

(1 pt) Which answer is the same as moving the decimal in 6.73 three places to the left? A. dividing 6.73 by 103 B. dividing 6.73

zalisa [80]

D. because when you multiply you move your numbers to the left and 1000 has 3 zeros meaning you will move your answer 3 times to the left .

hope you understand
good luck with your homework

4 0

3 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

2 years ago