Composite of 2,23,37,42
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Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.
What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So
has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
6
Step-by-step explanation:
h = 8
Surface area = 66π
2πr(r +h) = 66π
2πr(r + 8) = 66π
r² + 8r = 33
r² + 8r - 33 = 0
r² + 11r - 3r - 33 = 0
r(r + 11) - 3(r + 11) = 0
(r +11 ) (r - 3) = 0
r - 3 = 0 {Ignore r = -11 as radius will not have negative value}
r = 3
Diameter = 3*2 = 6 units