Answer:
D
Step-by-step explanation:
(-7x^2 - 3) + (4x - 6)
-3 - 6 = -9
-7x^2 + 4x - 9
Answer:
Diagram attached
AJ = 8.75 in.
Step-by-step explanation:
Since triangles HBA & HKJ are similar,
BH/AH = KH/JH
3 in /5.25 in = 8 in /JH
JH = 14 in
JA = JH - AH = JH - 5.25 in = 8.75 in
HJ = 14 in.
AJ = 14 in - 5.25 in
AJ = 8.75 in.
Answer:
0.8753
Step-by-step explanation:
Calculate the probability that your job will be ready before 10.01 am
Here, the parameter of an Exponential is E(X)=12
Now, to calculate the third job probability, it follows Poisson Distribution with parameter 1/λ
Therefore, E(Y) =1/12
Here, The third job will be ready for 10:01 AM, then E(Y)=61/12
Therefore, the required probability is
![P(X\geq 3)=1-P(X](https://tex.z-dn.net/?f=P%28X%5Cgeq%203%29%3D1-P%28X%3C3%29%5C%5C)
=1- POISSON(3,5,true)
=1-0.1246
=0.8753
95% C.I. = mean + or - 1.96(standard deviation / sqrt(sample size))
95% C.I. = 57 + or - 1.96(3.5/sqrt(40) = 57 + or - 1.085 = 57 - 1.085 to 57 + 1.085 = 55.92 to 58.09
Therefore, 95% of the mean will occur in the interval 55.92 to 58.09
Answer:
![Amount = 66ft^3](https://tex.z-dn.net/?f=Amount%20%3D%2066ft%5E3)
Step-by-step explanation:
No attachment given, but the question can still be solved.
Given
<u>Cuboid 1</u>
![Height = 2ft](https://tex.z-dn.net/?f=Height%20%3D%202ft)
<u>Cuboid 2</u>
<u></u>
<u></u>
<u></u>
Required
How much plaster can fit in
To do this, we simply calculate the volume of the shape
<u>For cuboid 1</u>
![Volume = Length * Width * Height](https://tex.z-dn.net/?f=Volume%20%3D%20Length%20%2A%20Width%20%2A%20Height)
![V_1 = 1 * 1 * 2](https://tex.z-dn.net/?f=V_1%20%3D%201%20%2A%201%20%2A%202)
![V_1 = 2ft^3](https://tex.z-dn.net/?f=V_1%20%3D%202ft%5E3)
<u>For cuboid 2</u>
![V_2 = 4 * 4 * 4](https://tex.z-dn.net/?f=V_2%20%3D%204%20%2A%204%20%2A%204)
![V_2 = 64ft^3](https://tex.z-dn.net/?f=V_2%20%3D%2064ft%5E3)
Amount of plaster is then calculated as:
![Amount = V_1 + V_2](https://tex.z-dn.net/?f=Amount%20%3D%20V_1%20%2B%20V_2)
![Amount = 2ft^3 + 64ft^3](https://tex.z-dn.net/?f=Amount%20%3D%202ft%5E3%20%2B%2064ft%5E3)
![Amount = 66ft^3](https://tex.z-dn.net/?f=Amount%20%3D%2066ft%5E3)