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Dima020 [189]
3 years ago
5

Find the unit rate. 56 apples in 7 boxes

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

8 Apples in each box.

Step-by-step explanation:

56/7=8 Or, 7x_=56

                    ^8 , if you start multiplying from 1-8.

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Write a word problem between 9 and 6
Gre4nikov [31]
There are 6 children that ate 9 cookies what is the ratio of the children and cookies?

Hope this helps!
4 0
3 years ago
What do u add to 5 3/7 to make 7
Lisa [10]

Answer:

1 11/38

Step-by-step explanation:

7 divided by 5 3/7 and you get 49/38 simplify by divided the the top by the bottom and you should get 1 11/38

5 0
3 years ago
Hi! I have a question and I don't understand it's answer. Could you help me?It's in the attachment below.
Paladinen [302]

To solve this question, we just need to evaluate our set of points in the standard form equation of a Hyperbola, and find the coefficients. This will give to us the equation for our Hyperbola. The standard form is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

Let's start with the easier points, the x-intercepts (5, 0) and (-1, 0).

Since this hyperbola has two x-intercepts, we're dealing with a horizontal hyperbola, and the center is the midpoint between the x-intercepts.

\begin{gathered} \bar{x}=\frac{x_1+x_2}{2}=\frac{-1+5}{2}=2 \\ \bar{y}=\frac{y_1+y_2}{2}=\frac{0+0}{2}=0 \end{gathered}

The center coordinates are (2, 0), then, our equation is

\frac{(x-2)^2}{a^2}-\frac{y^2}{b^2}=1

To find the missing coefficients, we can just substitute the remaining points and solve the system for a and b. Our final equation is

\frac{(x-2)^2}{9^{}}-\frac{y^2}{4}^{}=1

6 0
1 year ago
Screenshot of question below
koban [17]

Answer:

231 yd²

Step-by-step explanation:

h·b=A

17.5 · 13.2 = 231 yd²

8 0
2 years ago
Read 2 more answers
If f(x)=8-5x, find each value<br> 1. f(4c)<br> 2. f(2-k)<br> 3. f(4p+3)<br> Please and thanks!
Studentka2010 [4]

Problem 1

We replace every copy of x with 4c and simplify like so:

f(x) = 8 - 5x

f(4c) = 8 - 5*4c

f(4c) = 8 - 20c is the answer

This is equivalent to -20c+8.

====================================================

Problem 2

Same idea as before, but this time we'll plug in x = 2-k

Each x gets replaced with (2-k)

f(x) = 8 - 5x

f(2-k) = 8 - 5(2-k)

f(2-k) = 8 - 10 + 5k

f(2-k) = -2 + 5k

This is the same as saying 5k - 2.

====================================================

Problem 3

The steps are similar to earlier.

f(x) = 8 - 5x

f(4p+3) = 8 - 5(4p+3)

f(4p+3) = 8 - 20p - 15

f(4p+3) = -7-20p

This is the same as writing -20p - 7.

7 0
1 year ago
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