How does acid (vinegar) react with a metal (paperclip)
1 answer:
You might be interested in
Hello!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
![pH=pKa+log( \frac{[CH_3NH_2]}{[CH_3NH_3Cl]} )=10,65+log( \frac{0,18M}{0,73M} )=10,04](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3Cl%5D%7D%20%29%3D10%2C65%2Blog%28%20%5Cfrac%7B0%2C18M%7D%7B0%2C73M%7D%20%29%3D10%2C04)
So, the pH of this buffer solution is 10,04
Have a nice day!
First, we need to determine the pKa of the base. It can be found applying the following equation:
Now, we can apply the Henderson-Hasselbach's equation in the following way:
So, the pH of this buffer solution is 10,04
Have a nice day!
Answer : The mass of sulfuric acid needed is .
Solution : Given,
pH = 8.94
Volume of solution = 380 ml =
Molar mass of sulfuric acid = 98.079 g/mole
As we know,
Now we have to calculate the moles of .
Formula used :
For neutralization, equal number of moles of ions will neutralize same number of
ions.
As,
From this reaction, we conclude that
2 moles of ion is given by the 1 mole of
moles of
ion is given by
moles of
Now we have to calculate the mass of sulfuric acid.
Mass of sulfuric acid = Moles of × Molar mass of sulfuric acid
Mass of sulfuric acid =
Therefore, the mass of sulfuric acid needed is .