The pH of a solution is a measure used to evaluate the acidity of a solution. It is related to the hydronium ion concentration in the solution. It is expressed as pH = -log [H+]. Also, it is related to pOH by the equation 14 = pH + pOH. It is stated that the substance given in the problem is a strong base which means that it completely dissociates into ions. It dissociates as follows:
Ba(OH)2 = Ba^2+ + 2OH-
To determine the pH of the solution, we need to determine the OH- concentration. Then, find pOH. We do as follows:
[OH-] = 0.0064 mol Ba(OH)2 / L ( 2 mol OH- / 1 mol Ba(OH)2 ) = 0.0128 mol OH- / L
pOH = -log (0.0128) = 1.8928
pH = 14 - 1.8928 = 12.1072
Potassium Selenium = K2Se
Answer: 2.22 litres
Explanation:
Given that,
Original pressure of gas (P1) = 200.0 kPa
[Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere
If 101.325 kPa = 1 atm
200.0 kPa = 200.0/101.325
= 1.9738 atm]
Original volume of oxygen O2 (V1) = 25.5L
New pressure of gas (P2) = 11.2 atm
New volume of gas (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P2V2
0.9738 atm x 25.5L = 11.2 atm x V2
24.8319 atm•L = 11.2 atm•V2
Divide both sides by 11.2 atm to get V2
24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm
2.217 L = V2
[Round 2.217L to the nearest hundredth as 2.22L]
Thus, the new volume of the gas at 11.2 atm of pressure is 2.22 litres
Firework exploding. Thank you :)
Answer:
option D - coking or fouling
Explanation:
Coking (not cocking) is the process involving the deposition of small carbon particles (created by simply putting carbon atoms) on a catalyst's accessible surface, leading in a reduction in the area accessible for catalytic activity. This is also sometimes related to fouling catalysts or merely fouling them.