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3 years ago

Solve each inequality 2>6/6-1

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

Answer:

2 > 0

Step-by-step explanation:

2 > 6/6 - 1

2 > 1 - 1

2 > 0

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What's the algebraic expression for n cubed increased by 5??

sertanlavr [38]

N^3+5 is the algebraic expression for it.

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3 years ago

PLEASE Help! <br><br> How much larger is 3 to the 5th power than 5 to the 3rd power?

grandymaker [24]

Well 3 to the 5th power is 243 and 5 to the 3rd power is 125 and 243-125 is 118

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4 years ago

775 tickets were sold for a game for a total of 1,187.50. If adults tickets sold for 2.50 and children's tickets sold for 1.00 h

Ivanshal [37]

Answer: 275 adult tickets and 500 children's tickets were sold.

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of children's tickets that were sold.

775 tickets were sold for the game. It means that

x + y = 775

If adults tickets sold for 2.50 and children's tickets sold for 1.00 and all the tickets were sold for a total of 1,187.50, it means that

2.5x + y = 1187.5

Substituting x = 775 - y into equation 1, it becomes

2.5(775 - y) + y = 1187.5

1937.5 - 2.5y + y = 1187.5

- 2.5y + y = 1187.5 - 1937.5

- 1.5y = - 750

y = - 750/ - 1.5

y = 500

x = 775 - y = 775 - 500

x = 275

6 0

3 years ago

Solve for a<br>How do you solve this

8_murik_8 [283]

Answer:

2.2

Step-by-step explanation:

To find a, you use a formula called the law of cosines:

The law of cosines tells us:

a^2 = b^2 + c^2 - 2bc cosA

So lets plug in the values:

a^2 = 4^2 + 3^2 -2(4)(3)cos(32)

a^2 = 25-24cos32

a^2 is roughly equal to 4.97

therefore a roughly equal to 2.2

6 0

3 years ago

What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min

Ilya [14]

Answer:

Value of expression in single logarithm is $\log_3\left(2z^2\right)$ .

Step-by-step explanation:

Given expression is,

$2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)$

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

$\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)$

Therefore,

$2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)$

Applying power rule of logarithmic,

$a\log_c\left(b\right)=\log_c\left(b^a\right)$

Therefore,

$\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)$

$\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)$

Applying quotient rule of logarithmic,

$\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)$

Therefore,

$\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)$

Simplifying,

$\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)$

$\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)$

$\log_3\left(2z^2\right)$

Therefore value of expression is $\log_3\left(2z^2\right)$

6 0

4 years ago

Read 2 more answers