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Travka [436]
3 years ago
12

Solve each inequality 2>6/6-1

Mathematics
1 answer:
natka813 [3]3 years ago
6 0

Answer:

2 > 0

Step-by-step explanation:

2 > 6/6 - 1

2 > 1 - 1

2 > 0

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What percent of 130 is 9
Rudik [331]
The answer is 6.92%
6 0
3 years ago
What are the roots of the polynomial equation
rosijanka [135]

Answer:

-4 or -3

Step-by-step explanation:

Calculate the determinant:

D = b^2 - 4ac = 49 - 48 = 1

Apply the formula:

x = (-b +- sqrt(D))/2a = (-7 +- 1)/2 = -4 or -3

7 0
2 years ago
What is 10 of 25%......................................
tia_tia [17]


the math behind it: 
your equation looks like this: .25x = 10 
then you divide both sides by .25 and then ur equation looks like this: x=40 
by the way the variable x stands for the number you are looking for. and since x=40, the number you are looking for is 40 
well i hope i helped!
3 0
3 years ago
Tanya is training a turtle for a race. For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile. At wh
vazorg [7]

Answer:

\frac{6}{20} \ mile\ per\ hour

Step-by-step explanation:

Given:

For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile

Question asked:

At what unit rate is the turtle crawling?

Solution:

As here<u> time taken is given</u> and the <u>distance traveled is also given </u>and hence we will apply speed and distance formula to find rate of crawling of turtle.

Time taken by turtle = \frac{1}{2} \ hour

Distance which can be traveled by turtle = \frac{3}{20} \ miles

Speed =\frac{Distance}{Time}

         =\frac{3}{20} \div\frac{1}{2} \\\\ =\frac{3}{20} \times\frac{2}{1} \\ \\ =\frac{6}{20}

Therefore, the rate at which the turtle is crawling is \frac{6}{20} \ mile\ per\ hour

4 0
3 years ago
A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant prod
-Dominant- [34]

Answer:

Step-by-step explanation:

Given that a farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces

When we consider this graph as a straight line, the two points lying on the line would be

(30, 30) and (34, 28) taking n as horizontal and y vertical

Using two point equation we find that

the equation of the line is

\frac{y-y_1}{y_2-y_1} =\frac{x-x_1}{x_2-x_1}

Substitute the points as x =n

\frac{y-30}{28-30} =\frac{x-30}{34-30}\\y-30 = -0.5(x-30)\\y = -0.5x+45

is the linear relationship between n and y

7 0
3 years ago
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