Answer:
a) r ⋀~p
b)(r⋀p)⟶q
c) ~r ⟶ ~q
d) (~p ⋀r) ⟶q
Step-by-step explanation:
To solve this question we will make use of logic symbols in truth table.
We are told that;
p means "The user enters
a valid password,”
q means “Access is granted,”
r means “The user has paid the
subscription fee”
A) The user has paid the subscription fee, but does not enter a valid
password.”
Fist part of the statement is correct and so it will be "r". Second part of the statement is a negation and will be denoted by ~p. Since both statements are joined together in conjunction, we will use the conjuction symbol in between them which is "⋀" Thus, we have; r ⋀~p
B) Still using logic symbols, we have;
(r⋀p)⟶q
⟶ means q is true when r and p are true.
C) correct symbol is ~r ⟶ ~q
Since both statements are negation of the question. And also, if ~r is true then ~q is also true.
D) Similar to answer A to C above, applying similar conditions, we have (~p ⋀r) ⟶q
Answer:
Its B
Step-by-step explanation:
I did the test on edge
Explanation:
The expression f(0) represents the value of the function at x=0 which means the y-intercept of the function.
the y-intercept of the graph is the point that crosses the y-axis.
From the given graph,
The y-intercept of the graph does not define.
Answer: f(0) = not defined
Answer:
a = x-intercept(s): (
3
,
0
)
y-intercept(s):
(
0
,
6
)
B = x-intercept(s):
(
10
,
0
)
y-intercept(s):
(
0
,
4
)
Step-by-step explanation:
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