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2 years ago

Please help me on this question! Thank You!

Mathematics

2 answers:

GaryK [48]2 years ago

5 0

Answer:

the first one should be 23 but I don't know about the other one sorry

Zolol [24]2 years ago

4 0

Y=6.75 inches and X=2.25 inches

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Solve for y.<br> - 4+v=6

Leviafan [203]

Answer: v=10

Step-by-step explanation:

since you didn’t put a y on there, I solved for v.

3 0

3 years ago

What is the product of 8/15 and 2 3/4?

Black_prince [1.1K]

The correct answer is 1 7/15.

4 0

2 years ago

Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.

muminat

Answer:

1. $12x^2-13.4x-11$

- Degree: 2

- Number of terms: 3

2. $7x^3+168$

- Degree: 3

- Number of terms: 2

3. $9x^4-9$

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

1. Given:

$(4x + 2.2)(3x - 5)$

Apply the Distributive property:

$=12x^2+6.6x-20x-11$

Add the like terms:

$=12x^2-13.4x-11$

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

$(-304 +503 - 12) + (7x^3 - 25 + 6)$

Add the like terms:

$=187 + 7x^3 - 25 + 6=7x^3+168$

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

$(3x^2 - 3)(3x^2 + 3)$

Apply Distributive property:

$=9x^4-9x^2+9x^2-9$

Add the like terms:

$=9x^4-9$

You can idenfity that:

- Degree: 4

- Number of terms: 2

8 0

3 years ago

A system of equations is shown below.

Nimfa-mama [501]

-3x + 7y = -16 . . . (1)
-9x + 5y = 16 . . . .(2)

(1) x 3 => -9x + 21y = -48 . . . (3)
(2) - (3) => -16y = 64 . . . (4)

Required equivalent system of equations is
-9x + 5y = 16
-16y = 64

5 0

2 years ago

Louisa ran at an average speed of five miles per hour along an entire circular park path. Calvin ran along the same path in the

docker41 [41]

Answer:

15 miles

Step-by-step explanation:

Let $x$ be the miles in the circular park path, $t_{L}$ the time Louisa takes to finish and $t_{C}$ the time Calvin takes to finish both in hours.

Then $x$ , the longitude is equal to the velocity times the time used to finish. So

$x=5t_{L}$

$x=6t_{C}$

And the difference between Louisa's time and Calvin' time is 30 minutes, half an hour. So:

$t_{C}=t_{L}-0.5$

Three equations, three unknowns, the system can be solved.

Equalizing the equation with x :

$5t_{L}=6t_{C}$

In this last equation replace $t_{C}$ with the other equation and solve:

$5t_{L}=6(t_{L}-0.5)\\ 5t_{L}=6t_{L}-3\\ 3=6t_{L}-5t_{L}\\ 3=t_{L}\\ t_{L}=3$

With Louisa's time find x:

$x=5t_{L}\\ x=5(3)\\ x=15$

7 0

2 years ago